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sergey [27]
3 years ago
13

Give an example of two numbers that are both 6-digit numbers,but the greater number is Determined by the hundreds place

Mathematics
1 answer:
VMariaS [17]3 years ago
5 0

perhaps 300,900 and 300,400 ?

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Better buy water at target
Mice21 [21]

Answer:

Correct

Step-by-step explanation:

Shop Target for Water you will love at great low prices. Free shipping on orders of $35+ or same-day pick-up in store.

3 0
3 years ago
Read 2 more answers
X² - xy = 0<br> x + y = 1
wolverine [178]

Answer:

(0, 1 ) and (\frac{1}{2}, \frac{1}{2} )

Step-by-step explanation:

Given the 2 equations

x³ - xy = 0 → (1)

x + y = 1  → (2) ( subtract x from both sides )

y = 1 - x → (3)

Substitute y = 1 - x into (1)

x² - x(1 - x) = 0

x² - x + x² = 0

2x² - x = 0 ← factor out x from each term on the left side

x(2x - 1) = 0

Equate each factor to zero and solve for x

x = 0

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \frac{1}{2}

Substitute these values into (3) for corresponding values of y

x = 0 : y = 1 - 0 = 1 ⇒ (0, 1 )

x = \frac{1}{2} : y = 1 - \frac{1}{2} = \frac{1}{2} ⇒ ( \frac{1}{2}, \frac{1}{2} )

3 0
3 years ago
1/2x - 7 = 1/3(x-12) what is x?
sashaice [31]

Answer:

x = 18

Step-by-step explanation:

took test!!

7 0
3 years ago
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Juan wants to make a new game board that is a grid containing 25 equally sized squares. How many squares should be shaded to cre
pickupchik [31]

Let the number of shaded square be x. And it is given that total number of squares are 25.

probability = \frac{shaded \ squares}{total \ squares}

Substituting the values

0.2 = \frac{x}{25}

Performing cross multiplication

0.2*25=x \\ x = 5

So 5 squares should be shaded to create a region with a geometric probability of 0.2 .

8 0
3 years ago
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What is the average rate of change of the function on the interval from x = 0 to x = 5?
crimeas [40]

Answer:

Average rate of change =\frac{1}{8}

Step-by-step explanation:

Given interval are from x=0\ to\ x=5

Also,=\frac{1}{2^3}x=\frac{1}{8}x

Average rate of change=\frac{f(b)-f(a)}{b-a}\ for\ given\ interval\ [a,b]

Here given intervals are a=0\ and\ b=5

Plugging these value in formula, we get.

Average rate of change=\frac{\frac{1}{8}(5)-\frac{1}{8}(0)}{5-0}\\\\=\frac{\frac{1}{8}(5)-0}{5-0}\\ \\=\frac{\frac{1}{8}(5)}{5}\\\\=\frac{1}{8}

4 0
3 years ago
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