Help I need a awnser

The midpoint of KL is M (-8,1). One endpoint is K (-6,5) find the coordinates of the other endpoint L

PSYCHO15rus [73]

Answer:

Midpoint (x , y) of two points is

( x1 + y1/2 , x2 + y2/2)

Midpoint of KL is M ( -8 , 1)

Let the coordinates of L be ( a , b)

From the above definition

Midpoint between K(-6 , 5) and

L ( a ,b) is

(-8 , 1) = ( -6+a/2 , 5+b/2)

Comparing first point with - 8

- 8 = -6 + a /2

Multiply through by 2

We get

-16 = - 6 + a

a = -16+6

a = - 10

Comparing the second point with 1

1 = 5+b/2

Multiply through by 2

2 = 5 + b

b = 2 - 5

b = -3

Therefore a = -10 and b = - 3

Hence the coordinates of

L is ( -10 , - 3)

Hope this helps

3 0

3 years ago

.98*125<br> 13.75*12<br> 143.43/31

vova2212 [387]

Answer:

n = 6

n, = 6n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2

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3 0

3 years ago

A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d

nikitadnepr [17]

Answer:

a) k=2.08 1/hour

b) The exponential growth model can be written as:

$P(t)=Ce^{kt}$

c) 977,435,644 cells

d) 2.033 billions cells per hour.

e) 2.81 hours.

Step-by-step explanation:

We have a model of exponential growth.

We know that the population duplicates every 20 minutes (t=0.33).

The initial population is P(t=0)=58.

The exponential growth model can be written as:

$P(t)=Ce^{kt}$

For t=0, we have:

$P(0)=Ce^0=C=58$

If we use the duplication time, we have:

$P(t+0.33)=2P(t)\\\\58e^{k(t+0.33)}=2\cdot58e^{kt}\\\\e^{0.33k}=2\\\\0.33k=ln(2)\\\\k=ln(2)/0.33=2.08$

Then, we have the model as:

$P(t)=58e^{2.08t}$

The relative growth rate (RGR) is defined, if P is the population and t the time, as:

$RGR=\dfrac{1}{P}\dfrac{dP}{dt}=k$

In this case, the RGR is k=2.08 1/h.

After 8 hours, we will have:

$P(8)=58e^{2.08\cdot8}=58e^{16.64}=58\cdot 16,852,338= 977,435,644$

The rate of growth can be calculated as dP/dt and is:

$dP/dt=58[2.08\cdot e^{2.08t}]=120.64e^2.08t=2.08P(t)$

For t=8, the rate of growth is:

$dP/dt(8)=2.08P(8)=2.08\cdot 977,435,644 = 2,033,066,140$

(2.033 billions cells per hour).

We can calculate when the population will reach 20,000 cells as:

$P(t)=20,000\\\\58e^{2.08t}=20,000\\\\e^{2.08t}=20,000/58\approx344.827\\\\2.08t=ln(344.827)\approx5.843\\\\t=5.843/2.08\approx2.81$

3 0

3 years ago

write the first four terms of the sequence defined by the given rule f (1) = 3, f(n) = [ f(n - 1)] ^2

AleksandrR [38]

Answer:

3, 9, 81, 6561

Step-by-step explanation:

previous term × itself

8 0

2 years ago

Read 2 more answers

Which equation represents the situation Please help me

Virty [35]

100 dollars should be a one time fee so that has to be added to the equation, and since it is a one time fee it should not have a variable next to it.

It also says that you have to pay 720 dollars per month, so it has to have a variable next to it to show the number of months that she needs to pay that amount of money.

The answer should be D.

y= 720x +100

4 0

2 years ago

Read 2 more answers