After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.
After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.
And so on. After t years, the investment would have a value of
.
We want the find the number of years n such that

Solve for n :





21000=a+b
ax.075xt=6xbx.04xt
t cancels out
a=3.2b
21000= 3.2b+b
21000=4.2b
b=5000
a=16000
account with 7.5% had 16000 invested in it.
account with 4% had 5000 invested in it
Answer:
44.52 inches
Step-by-step explanation:
If it grows 3.71 inches per month for 12 months, you need to multiply 3.71 by 12, which gives you 44.52.
Hello from MrBillDoesMath!
Answer:
20
Discussion:
Let (x1,y1) = (-8, -6) and (x2,y2) = (4,10). Per the distance formula,
Distance = sqrt ( (x1-x2)^2 + (y1-y2)^2 ) so
Distance = sqrt ( (-8-4)^2 + (-6-10)^2 )
= sqrt( (12)^2 + (-16)^2 )
= sqrt( 144 + 256 )
= sqrt(400)
= 20
Thank you,
MrB