Answer:

Step-by-step explanation:
Given


Required:
Calculate the angle between u and v
The angle
is calculated as thus:

For a vector


becomes




For a vector


So;






So:






Take arccos of both sides





<em></em>
<em> (approximated)</em>
Perimeter of a rectangle is given by (2 × Length(l)) + (2 × Width(w)) = 2l + 2w
l= 11 feet
2(11) + 2w = 46
2w = 46 - 22 = 24
w = 24/2 = 12 feet
Width = 12 feet.
If the problem looks like mine, the answer is 152.
Y= Mx+b
In the equation of a straight line,the slope is the number "m" that is multiplied on the x, and "b<span>" is the </span>y<span>-intercept (that is, the point where the line crosses the vertical </span>y<span>-axis).</span>
Answer:
5 students
Step-by-step explanation:
2/3 of 30 = 20 students
1/4 of 20 = 5 students