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tresset_1 [31]
1 year ago
15

EGR2 phosphatase regulates OST1 kinase activity and freezing tolerance in Arabidopsis. EMBO J. 38: e99819.

Biology
1 answer:
Zigmanuir [339]1 year ago
4 0

Active PDK:

Acetyl CoA

NADH

Inhibit PDK:

NAD+

coenzyme A

ADP

This same PDK is enabled and inhibited thru all the ADP, NAD+, and key enzymes Thorough assessment of Acetyl CoA and NADP. In PDC, the methylation of its Ser residues, which have been catalyzed by PDK, inhibits the pyruvate dehydrogenase.

Learn more about pyruvate dehydrogenase here brainly.com/question/22683408

#SPJ4.

The activity of the pyruvate dehydrogenase complex is also controlled by phosphorylation. Pyruvate dehydrogenase kinase (PDH kinase) catalyzes the phosphorylation of a specific Ser residue on the E1 subunit of the enzyme, rendering it inactive. Pyruvate dehydrogenase phosphatase (PDH phosphatase) reverses the inhibition by catalyzing the removal of this phosphate group. The PDH kinase is highly regulated and its activity is influenced by various cellular metabolites. Indicate whether the following would activate or inhibit PDH kinase:

Inhibit or activate PDK?

NAD+

NADH

coenzyme A

acetyl-CoA

ADP

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Spores and seeds have basically the same function-dispersal-but are vastly different because spores ________. (A) have a protect
sweet-ann [11.9K]

Spores and seeds have basically the same function-dispersal-but are vastly different because spores (D) are unicellular; seeds are not.

<h3>What are  unicellular organism?</h3>

A unicellular organism can be regarded as  single-celled organism, which are those organisms  that consists of a single cell.

This is different from   multicellular organism  because it consists of multiple cells however  Organisms  can be selected base on  general categories which are  prokaryotic organisms and eukaryotic organisms.

It should be noted that Spores and seeds have basically the same function-dispersal-but are vastly different because spores (D) are unicellular; seeds are not.

Therefore option D is correct.

Read more about Spores here:

brainly.com/question/3529377

#SPJ1

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4 0
3 years ago
Which of these statements are accurate? Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group fr
Agata [3.3K]

Answer:

A. The conformational shift that occurs when glucose, but not water, enters the active site prevents water from hydrolyzing ATP. True

B. Hexokinase consists of two domains, or lobes, that come together when glucose and the MgATP2–MgATP2– complex are bound. True  

C. Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. True

Explanation:

A. Hexokinase suffers and conformational changes by binding glucose in a reaction that prevents ATP hydrolysis.

B. Hexokinase is an enzyme with two domains that function by binding to the substrate (i.e., glucose). The region linking both protein domains is responsible for the catalytic activity.

C. Hexokinase is a type of transferase that catalyzes the transfer of a phosphoryl group from ATP to a hexose. During the first stage of glycolysis, the hexokinase transfers one phosphorous group from magnesium-ATP (Mg-ATP) to one hexose molecule, such as fructose, mannose or glucose.

 

False statements:

- Most kinases require the presence of a monovalent metal ion cofactor to prevent ATP hydrolysis. False: In canonical kinases, conserved amino acids bind to divalent metal ions before the transference of the phosphate group to their substrates.

- Hexokinase is found in the mitochondrial membrane. False: Hexokinase is found in the cytosol.

- Hexokinase transfers the terminal phosphate of ATP to carbon 3 of glucose. False: Hexokinase catalyzes the transfer of the terminal phosphate ATP to form glucose 6-phosphate.

5 0
3 years ago
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