Here is a list showing how the bacteria grows:
Begin - 15
1st hour - 30
2nd hour - 60
3rd hour - 120
4th hour - 240
5th hour - 480
6th hour - 960
7th hour - 1,920
8th hour - 3,840
9th hour - 7,680
10th hour - 15,360
11th hour - 30,720
12th hour - 61,440
As you can see, the number of bacteria present is doubled at the end of each hour, as the question states. However, the question is not asking for the total number of bacteria at the end of the 12th hour; it is asking for the bacteria GROWN during the 12th hour.
Because there were 30,720 bacteria at the end of the 11th hour, and 61,440 at the end of the 12th, the number of bacteria that grew during that last hour must be 61,440 - 30,720 = 30,720 bacteria.
(P.S. the answer would be 61,440 if it was asking for the TOTAL number of bacteria at the end of the 12th hour)
The medulla controls breathing and heart rate. hope this helps!
(could you please mark brainliest? Thanks!)
Answer: Pacific Northwest Animals & Birds
- Spotted and snowy owls.
- Bald and Golden eagles.
- Pileated woodpecker.
- Rufous hummingbird.
- Great Blue Heron and Canada goose.
- Seabirds, including cormorant.
- Bear.
- Olympic marmot.
Kitsap Peninsula:
Marine mammals of the sound include orcas, sea lions, sea otters, gray whales, humpback whales, and harbor seals. Underwater plants provide food, breeding areas, nurseries, and resting places for wildlife in the sound.
Answer:
C. 1/4
Explanation:
Let's assume that the allele for the spotted coat is "S" and the one for the even coat is "s". The allele "L" gives short horns while the recessive allele "l" imparts long horns. The genotype of the cattle heterozygous for both traits would be SsLl. A cross between two heterozygous cattle would produce progeny in following phenotype ratio=
9 spotted coat and short horns: 3 even coat and short horns: 3 spotted coat and long horns: 1 even coat and long horns.
Therefore, the proportion of the progeny with long horns = 4/16= 1/4
