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1 year ago

Please help me out please please please

Mathematics

2 answers:

natulia [17]1 year ago

7 0

Answer:

-18 + 30 s - 72 t + 12 u

Step-by-step explanation:

Expand the following:

-6 (3 - 5 s + 12 t - 2 u)

-6 (3 - 5 s + 12 t - 2 u) = -6×3 - 6 (-5 s) - 6×12 t - 6 (-2 u):

-6×3 - 6 (-5) s - 6×12 t - 6 (-2) u

-6×3 = -18:

-18 - 6 (-5) s - 6×12 t - 6 (-2) u

-6 (-5) = 30:

-18 + 30 s - 6×12 t - 6 (-2) u

-6×12 = -72:

-18 + 30 s + -72 t - 6 (-2) u

-6 (-2) = 12:

Answer: -18 + 30 s - 72 t + 12 u

Musya8 [376]1 year ago

7 0

Answer:

Step-by-step explanation:

-18 + 30s - 72t + 12u

Answer is Option 2

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xenn [34]

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3 years ago

Which place is the tenths and what is it rounded to? please answer quick thx

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

see attached to identify which is the tenth's place

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3 years ago

Find a formula for dy/dx if sin x + cos y + sec(xy) = 251

Lena [83]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}$

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Factoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Trig Differentiation

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Implicit Differentiation

Step-by-step explanation:

Step 1: Define

Identify

sin(x) + cos(y) + sec(xy) = 251

Step 2: Differentiate

[Implicit Differentiation] Trig Differentiation [Chain Rule]: $\displaystyle cos(x) - sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = 0$
[Subtraction Property of Equality] Isolate $\displaystyle \frac{dy}{dx}$ terms: $\displaystyle -sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = -cos(x)$
[Distributive Property] Distribute sec(xy)tan(xy): $\displaystyle -sin(y)\frac{dy}{dx} + ysec(xy)tan(xy) + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x)$
[Subtraction Property of Equality] Isolate $\displaystyle \frac{dy}{dx}$ terms: $\displaystyle -sin(y)\frac{dy}{dx} + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x) - ysec(xy)tan(xy)$
Factor out $\displaystyle \frac{dy}{dx}$ : $\displaystyle \frac{dy}{dx}[-sin(y) + xsec(xy)tan(xy)] = -cos(x) - ysec(xy)tan(xy)$
[Division Property of Equality] Isolate $\displaystyle \frac{dy}{dx}$ : $\displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}$