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lisabon 2012 [21]
2 years ago
6

Can you please answer my homework, its about sets.

Mathematics
1 answer:
Katyanochek1 [597]2 years ago
6 0

The value of the set  (A∪C)'∩B is {9 , 12} .

A subfield of mathematical logic called set theory examines sets, which are essentially collections of objects.

  • Set theory is a discipline of mathematics that largely addresses problems that are pertinent to mathematics as a whole, despite the fact that any kind of object can be constructed into a set.
  • Set theory is founded on a simple binary relationship between an object o and a set A.
  • It is written as o A if o is a part (or member) of A. Members of a set are enumerated with commas to denote separation when describing them, or a property of those parts is enclosed in braces.
  • Sets can be associated by the membership relation since they are objects.

The given sets are:

U ={1,2,3,4,5,6,7,8,9,10,11,12,13}

A = {3,7,11,13}

B = {3,6,9,12,13}

C = {2,3,5,6,7,8}

Now B' = {1,2,4,5,7,8,10,11}

b) B'∩C = {2,5,7,8,}

c) A∪C = {2,3,5,6,7,8,11,13}

(A∪C)' = {1,4,9,10,12}

(A∪C)'∩B = {9 , 12}

Hence the value of the set (A∪C)'∩B is {9 , 12} .

To learn more about set visit:

brainly.com/question/18877138

#SPJ1

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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
4 years ago
Charles owes $2,500 on a credit card. The card charges 12% interest compounded continuously. Write a formula that describes how
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Answer:

  see below

Step-by-step explanation:

The formula for the amount resulting from P earning interest at rate r continuously compounded is ...

  A = Pe^(rt)

for P=2500 and r=0.12, this becomes ...

  A = 2500e^(0.12t)

4 0
3 years ago
Use the elimination method to solve the system of equations. Choose the correct ordered pair. 
kiruha [24]
5x+3y=58
5x-3y=22
(3y gets cancelled bc 3y-3y=0,  then add 5x with 5x, so you're left with)
10x=80, (divide both sides by 10)
x=8
Now we look for y. So choose one formula from the two (let's say 5x + 3y=58)
Substitute x for 8 so it will look like---- 5(8)+3y=58
Multiply 5*8--- so you get --  40+3y=58
Subtract 40 from both sides and you're left with 3y=18
divide both sides by 3
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5 0
3 years ago
Read 2 more answers
What’s the area all sides meet at right angles
Marina86 [1]

Answer: 54

Step-by-step explanation: I separated it into 3 areas in my head and then added up 21+21+12 to get 54

7 times 3 is 21

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8 0
3 years ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

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and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

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2 years ago
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