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kompoz [17]
11 months ago
5

Anybody know the answer to this question?

Mathematics
1 answer:
arlik [135]11 months ago
4 0
Answer a ka gim tul hd shi kdi
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104, 137, 154, 131, x, mean= 130
defon
130x5=650
650-104=546
546-137=409
409-154=255
255-131=124
x=124
8 0
3 years ago
HURRRY PLEASE ANSWER I ONLY HAVE 5 MINN which expressions are equivalent to - 72 + (-6.5) + 2.5z + 4y - 1.5
STALIN [3.7K]

Answer:

fghwjklpkjqkhb cghdbhn bwn x wxhw hwbmx

Step-by-step explanation:

8 0
2 years ago
Andrea claims that 2,899 rounded to the nearest hundred is 3,000. Zoe claims that 2,899 rounded to the nearest thousand is 3,000
dusya [7]
A) Only Zoe is correct.
2,899 rounded to the nearest hundredth would be 2,900
6 0
3 years ago
What is the answer to this problem 75=3(-6n-5)
devlian [24]

Answer:

n=-5

Step-by-step explanation:

first you have to distribute the 3 to the -6 and the 5. In return u will get -18n and 15. then you have to cancel like terms. then you have to add 18 to the 75 which gives you 93. then you divide -18 by 93 which gives you -5.166 repeating... so all you have to do is round. your final answer will be -5.

5 0
3 years ago
I'm genuinely lost in any problems like this and my teachers are no help, I need help doing exponents in general, everything to
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

(-6n^{-3})^2

We can use the power of a product property, where:

(ab)^n=a^n\cdot b^n

So:

=(-6)^2\cdot(n^{-3})^2

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

(a^n)^k=a^{nk}

So:

(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}

So, all together, we have:

=(-6)^2\cdot(n^{-3})^2\\=36n^{-6}

6)

We have the expression:

-\frac{3x^0}{x^4}

First, note that anything to the zeroth power (except for 0) is 1, thus, x^0 is also 1. Simplify:

=-\frac{3}{x^4}

And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

x^n=\frac{1}{x^{-n}}

And vice versa:

\frac{1}{x^{-n}}=x^n

So, we can write the above as:

=-\frac{3}{x^4}\\=-\frac{3}{x^{-(-4)}}\\=-3x^{-4}

However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0
3 years ago
Read 2 more answers
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