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Svetradugi [14.3K]

3 years ago

10

Lazer Zone charges $15 plus $6 per person to play laser tag. Using the inequality 15+6≤75, find p, the maximum number of people

can play laser tag for $75
10
5
12
8

1 answer:

Murljashka [212]3 years ago

4 0

The answer to your question is 10

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The sum of two consecutive integers is -207

Maru [420]

Answer:

They would be -104 and -103.

Step-by-step explanation:

-103 + (-104)

= -103 - 104

= -207.

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Which graph represents the equation x=-2

mixas84 [53]

graph c

because the graph x = -2 is a vertical line at -2 on the x axis

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3 years ago

(4 + 3x + x2) + (6 – 9x + x2)

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3 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

The average discharge at the mouth of the Amazon River is 4,900,000 cubic feet per second. How much water is discharged from the

Misha Larkins [42]

Answer: Average discharge at the mouth of the Amazon River in 1 hour = $1.764\times 10^{10}$ cubic feet

Average discharge at the mouth of the Amazon River in 1 year= $3.66912\times10^{13}$ cubic feet[/tex]

Step-by-step explanation:

Given : The average discharge at the mouth of the Amazon River =4,900,000 cubic feet per second.

i.e. The average discharge at the mouth of the Amazon River in 1 second= 4,900,000 cubic feet

Since 1 hour = 3600 seconds

Then , the average discharge at the mouth of the Amazon River in 1 hour =

$4900000\times3600=17640000000$ cubic feet

Since , there are 2080 hours in a typical year.

Then, the average discharge at the mouth of the Amazon River in 1 year=

$2080\times17640000000\\\\=36,691,200,000,000=3.66912\times10^{13}$ cubic feet

6 0

2 years ago