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Klio2033 [76]
1 year ago
13

A box of mixed nuts packs weighs 16 1/2 ounces. Each mixed nuts pack weighs 1 3/8 ounces. How many mixed nuts snack packs are in

the box?
Mathematics
1 answer:
vfiekz [6]1 year ago
3 0

12 mixed nuts packs

Explanation:

The box weighs 16 1/2 ounces

1 mixed nut = 1 3/8 ounces

let the number of fruit mixed nut in the box = y

1 mixed nut = 11/8 ounces

y = 33/2 ounces

cross multiply:

\begin{gathered} 1(\frac{33}{2})\text{ = y(}\frac{\text{11}}{8}) \\ \frac{33}{2}=\frac{11y}{8} \end{gathered}\begin{gathered} 2(11y)\text{ = 33(8)} \\ 22y\text{ = 33(8)} \\ y\text{ = }\frac{33(8)}{22} \end{gathered}\begin{gathered} y\text{ = 264/22} \\ y\text{ = 12 mixed nuts} \end{gathered}

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3 years ago
The equation of line L is y=5x+1
vovikov84 [41]

Answer:

see explanation

Step-by-step explanation:

Parallel lines have equal slopes.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

L₁ is y = 5x + 1 ← in slope- intercept form

with slope m = 5

L₂ is 2y - 10x + 3 = 0 ( subtract - 10x + 3 from both sides )

2y = 10x - 3 ( divide all terms by 2 )

y = 5x - \frac{3}{2} ← in slope- intercept form

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3 0
2 years ago
If y = 8 cm, what is the area of the blue section of this shape?
Ivahew [28]

Answer:

56 cm squared

Step-by-step explanation:

First things first: Cop one triangle off the rectangle, and attach it to the other one, so the shape looks like a L

Now I can actually solve this:

The left side is 8 cm (because y = 8 cm)

The top is 10 cm

The middle is 6 cm

The inside left is 3 cm

And the very bottom is 2 cm

First, we'll solve for the newly constructed rectangle: 3 x 2. That equals 6.

Next, solve for the longer rectangle: 10 x 5. That's 50.

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7 0
2 years ago
On a class trip to the museum,5/8 of the students saw the dinosaurs and 7/8 of the students saw either the jewelry collection or
inessss [21]

\frac{2}{8} of students only saw jewelry collection

<em><u>Solution:</u></em>

Given that, On a class trip to the museum,5/8 of the students saw the dinosaurs

7/8 of the students saw either the jewelry collection or the dinosaurs

<em><u>To find: Fraction of students only saw jewelry collection</u></em>

From given statement,

Fraction of students saw dinosaur = \frac{5}{8}

Fraction of students saw either the jewelry collection or the dinosaurs = \frac{7}{8}

Therefore,

Fraction of students only saw jewelry collection = Fraction of students saw either the jewelry collection or the dinosaurs - Fraction of students saw dinosaur

\rightarrow \frac{7}{8} - \frac{5}{8} = \frac{7-5}{8} = \frac{2}{8}

Thus \frac{2}{8} of students only saw jewelry collection

8 0
3 years ago
I need help I don’t get it
Ahat [919]

Answer:

5 and 9

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3 multiplied by whatever z is plus 2 has to be 10 or more

6 0
2 years ago
Read 2 more answers
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