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3 years ago

F(x)=2x^2+3 and g(x)=x^2-7 find (f-g)(x)

Mathematics

2 answers:

Lynna [10]3 years ago

6 0

Answer:

$(f-g)(x)=x^2+10$

C is the correct option.

Step-by-step explanation:

We have been given that

$f(x)=2x^2+3\\\\g(x)=x^2-7$

The function (f-g)(x) can rewritten as

$(f-g)(x)=f(x)-g(x)$

Substituting the value of f(x) and g(x)

$(f-g)(x)=2x^2+3-(x^2-7)$

Distribute negative over the parenthesis

$(f-g)(x)=2x^2+3-x^2+7$

Now, combine the like terms

$(f-g)(x)=x^2+10$

C is the correct option.

Setler79 [48]3 years ago

5 0

C............................

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6 + 2(x)2
6 + 2(3)2
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=6 + 12
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3 years ago

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What number goes on top and how do you solve it.

vekshin1

So basically, each number is equal to the two numbers below it added together.

See, 7 = 3+4, 8 = 5 +3, etc.

So, the top would be 16 + 17.

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3 years ago

What is the answer to -6(4r+2)+5

RideAnS [48]

Answer:

-24r - 7

Step-by-step explanation:

-6(4r + 2) + 5

-24r - 12 + 5

-24r - 7

Best of Luck!

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3 years ago

How do I solve 2x-3y=-1. y=x-1

nlexa [21]

Hello!

You can put in y for the first equation

2x - 3(x - 1) = -1

Distribute the -3

2x - 3x + 3 = -1

Combine like terms

-x + 3 = -1

Subtract 3 from both sides

-x = -4

Since x is negative we can multiply both sides by -1 to make x positive

x = 4

We can put x into the second equation to get y

y = 4 - 1

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The answers are x = 4 and y = 3

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7 0

3 years ago

Read 2 more answers

Mike and Kate plan to save money for their wedding over a 20 month period. They will need to save $8,000 to help pay for the wed

tino4ka555 [31]

Answer:

Correct answer is d: Neither option A nor option B will allow them to meet their goal.

Step-by-step explanation:

Money needed for wedding: 8000 in 20 months

Set aside the same amount each month: 4000 over 12 months

which becomes $\frac{4000}{12}$ = $333.33

Months left: 8

Lets evaluate option A first:

Save $333.33 each month and postpone wedding for two months

so by adding two months: 10 months are left till wedding

Money save in 10 months: 10 × 333.33 = $3333.33

So total will become 4000 + 3333.33 = $7333.33 (Not feasible)

Lets evaluate options B:

Increase the amount of saving by $ 80:

Amount saved each months first year: 333.33

After adding 80: 333.33 + 80 = 413.33(amount saved each month in 8 months)

8 months are left to wedding:

so they will save 8 × 413.33 = $3306.64

Total will become: 4000 + 3306.64 = $7306.64(Not feasible)

So correct answer is d: Neither option A nor option B will allow them to meet their goal.

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3 years ago