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Phoenix [80]
3 years ago
6

Graph this. y−3=12(x+3)

Mathematics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

wassup

Step-by-step explanation:

Nonamiya [84]3 years ago
4 0
You can just type this equation into a graphing calculator and you will get a graph which would be your answer

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Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
bezimeni [28]

Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

Age​ (yr) when award was won Frequency 25​-34 31 35​-44 36 45​-54 12 55​-64 4 65​-74 6 75​-84 1 85​-94 2

If we order the data we got the following result. We assume that the midpoint is given by:

Midpoint= \frac{L.Limit +U.Limit}{2}

The Class.Width = U.Limit-L.Limit

And the limits are given by the lower and upper limit.

L.Limit  U.Limit Class W  Midpoint  Frequency   Limits

  25         34     34-25=9     29.5           31           [25-34]                

  35         44      44-35=9     39.5          36           [35-44]

  45         54      54-45=9     49.5           12           [45-54]

  55         64      64-55=9     59.5           4            [55-64]

  65         74       74-65=9     69.5           6            [65-74]

  75          84      84-75=9     79.5            1            [75-84]

  85          94      94-85=9     89.5           2           [85-94]

8 0
3 years ago
Help it is due tomorrow morning​
Leno4ka [110]
The true one

miguel save 60$ on 4 months

The false one

After 2 months miguel has 20$
6 0
3 years ago
Solve question 3 for <br> 41 points
Sever21 [200]

Answer:

(2)

Step-by-step explanation:

Our logarithmic expression is: ln(\frac{\sqrt{e} }{y^3} ).

Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

ln(\frac{\sqrt{e} }{y^3} )=ln(\sqrt{e} )-ln(y^3)

Also, we can write square roots as powers of one-half, so √e = e^{1/2}. There's another log property that: ln(a^b)=b*ln(a). We can apply that here for both the √e and the y³:

ln(\sqrt{e} )-ln(y^3)=\frac{1}{2} ln(e)-3ln(y)

Finally, note that ln(e) is just 1, so we have:

\frac{1}{2} ln(e)-3ln(y)=\frac{1}{2} -3ln(y)=\frac{1-6ln(y)}{2}

The answer is thus (2).

<em>~ an aesthetics lover</em>

7 0
3 years ago
The distance y (in miles) that a truck travels on x gallons of gasoline is represented by the equation y = 18x.
Lapatulllka [165]

Answer:

Not A Question

Step-by-step explanation:

6 0
3 years ago
How can I solve this quadratic using the square root properly?
Citrus2011 [14]

Answer:

x = <u>+</u>3

Step-by-step explanation:

4x² = 36

sqareroot both side we get,

√4x² = √36

2x = 6

x = 6/2

x = <u>+</u>3

Thus, The answer is <u>+</u>3

<u>-TheUnknown</u><u>S</u><u>cientist</u>

7 0
3 years ago
Read 2 more answers
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