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Komok [63]
3 years ago
5

What makes a constant term different from a term with a variable

Mathematics
1 answer:
olga55 [171]3 years ago
5 0

A constant term is always the same number ... 24 / 7 / 365 .

A variable, and any term with a variable in it, is variable.
You never know what number it may be, unless you get
an equation where the variable is connected to constants.

You might be interested in
Multiply both sides of the equation by 6.<br> {(4a + 1) = 2a<br> ? (4a + 1) = ?<br> a
solniwko [45]

Answer:

24a+6=12a

Step-by-step explanation:

6(4a+1)

24a+6

2a X 6= 12a

24a+6=12a

6 0
3 years ago
You can represent an odd integer whith the expression 2n+1, where n is any integer . Write and solve an equation to find three c
oksian1 [2.3K]
Any odd number can be expressed by 2n+1.

For example,  

2n+1=111
2n=110
n=110/2=55

means that 111 is 2n+1 for n=55


Thus if an odd number is 2a+1, the next few numbers are as follows:

2a+1, 2a+2, 2a+3, 2a+4, 2a+5

So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.


Back to our problem: 

three consecutive odd numbers whose sum is 63 are:

(2n+1)+(2n+3)+(2n+5)=63

6n+9=63

6n=63-9=54

n=54/6=9


2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23


Answer: 19, 21, 23



5 0
3 years ago
Jonus watches the second hand on an analog clock as it moves past the numbers. What is the
slega [8]

Answer:1/12 or 8.3

Step-by-step explanation:

5 0
3 years ago
Write an equation of the parabola in intercept form with x-intercepts of 12 and -6; and an axis of symmetry of (14, 4).
xenn [34]

Intercept form is: y = a(x - p)(x - q)  

It is given that:  p = 14, q = -6, x = 14, y = 4

4 = a(14 - 12)(14 - (-6))

4 = a(2)(20)

4 = 40a

\frac{4}{40} = \frac{40a}{40}

\frac{1}{10} = a

Answer: y = \frac{1}{10}(x - 14)(x + 6)



6 0
3 years ago
The pulse rates of 174 randomly selected adult males vary from a low of 39 bpm to a high of 111 bpm. Find the minimum sample siz
Daniel [21]

Answer:

a. The sample size is approximately 97 adults

Step-by-step explanation:

The given parameters are;

The number of adults surveyed, n = 174

The lowest value of the pulse rate = 39 bpm

The highest value of the pulse rate = 111 bpm

The level of confidence used for determining the sample size = 90%

The given sample mean = 3 pm of the population mean

a. The range rule of thumb states that the standard deviation is approximately one quarter (1/4) of the range

The range = 111 bpm - 39 bpm = 72 bpm

Therefore, the standard deviation, σ = 72 bpm/4 = 18 bpm

The sample size, 'N', is given as follows;

N = \dfrac{z^2 \cdot p \cdot q}{e^2}

Where;

N = The sample size

z = The confidence level, 90% (z-score at 90% = 1.645)

p·q = σ² = 18² = 324

e² = 3² = 9

N = \dfrac{1.645^2  \times 324}{3^2} = 97.4169

Therefore the appropriate sample size, N ≈ 97 adults.

8 0
3 years ago
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