Answer:
The 95% confidence interval for mean compressive strength is:
Step-by-step explanation:
We have a sample of n=12 specimens, with sample mean=3259.9 and sample standard deviation = 35.57.
We know the population is normally distributed.
For a 95% confidence interval and df=n-1=11, the t-statistic is t=2.201.
Then, the CI can be expressed as:
Answer: 135 grams of Zinc
Step-by-step explanation:
The ratio of Zinc to Copper in this scenario is 3:13 and in this jar there is 585 of Copper.
Using direct proportion, the grams of Zinc in the jar is:
3 : 13
x : 585
Cross -multiplying will give:
1,755 = 13x
x = 1,755/13
x = 135 grams of Zinc
2 × pi × 10 = 20pi or 62.83
Answer:im not sure sorry
Step-by-step explanation: