here is your ans........option D.commodity money.......
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Answer:
a soda cost .65 and chips cost 1.3
Step-by-step explanation:
i hope this helps
Answer:
I think it is A
Step-by-step explanation:
Answer:
h less-than 2
Step-by-step explanation:
Let
h ---> the number of hours
y ---> the total charge in dollars
we know that
The linear equation is slope intercept form is equal to

where
m is the slope or unit rate of the linear equation
b is the y-intercept or initial value of the linear equation
we have
<em>Grayson</em>
The slope is equal to 
The y-intercept is 
so
The total charge is equal to
----> equation A
<em>Ian</em>
The slope is equal to 
The y-intercept is 
so
The total charge is equal to
----> equation B
For what number of hours does Grayson charge more than Ian?
The inequality that represent this situation is

solve for x
Group terms


Divide by 10 both sides

Rewrite the expression
----> h less than 2 hours