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daser333 [38]
3 years ago
9

The answer plzzzzzzzzzz

Mathematics
2 answers:
erastovalidia [21]3 years ago
3 0
Add 7 and 2 you will get 9, therefore the length of the post is 9.
Vesna [10]3 years ago
3 0
The answer is 9 feet. It is 2 feet below ground level and 7 above, and if you add them together (7+2) you get a total of 9.
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A football team has a net yardage of -33 - yards on a series of plays. The team needs a net yardage of 10
sukhopar [10]

Answer: Assuming that it's 4th down the team would need 43 yards to get a net yardage of 10

Step-by-step explanation:

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3 years ago
Find the percent increase from 8 to 18
Aleonysh [2.5K]
The correct answer is 44.4%
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A farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. Find the maximum area he can close.
Margarita [4]

Answer:

Width of 37.5 feet and length of 50 feet will maximize the area.

Step-by-step explanation:

Let w represent width and l represent length of the pen.

We have been given that a farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. We are asked to find the dimensions that will maximize the area.

We can see from the attachment that the perimeter of the pens would be 4w+3l.

We can set our given information in an equation 4w+3l=300.

The area of the two pens would be A=2l\cdot w.

From perimeter equation, we will get:

w=\frac{300-3l}{4}

Substituting this value in area equation, we will get:

A=2l\cdot (\frac{300-3l}{4})

Since we need to maximize area, so we need to find derivative of area function as:

A=\frac{600l-6l^2}{4}

Bring out the constant:

A=\frac{1}{4}*\frac{d}{dl}(600l-6l^2)

A=\frac{1}{4}*(600-12l)

A=150-3l

Now, we will set our derivative equal to 0 as:

150-3l=0

150=3l

\frac{150}{3}=\frac{3l}{3}

50=l

Now, we will substitute l=50 in equation w=\frac{300-3l}{4} to solve for width as:

w=\frac{300-3(50)}{4}

w=\frac{300-150}{4}

w=\frac{150}{4}

w=37.5

Therefore, width of 37.5 feet and length of 50 feet will maximize the area.

8 0
3 years ago
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djverab [1.8K]

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Step-by-step explanation:

subtract 2/3 from each side

x = 5 1/3

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For which acute angle are the sine of the angle and cosine of the angle equal? 30º 45º 60º 75º
Damm [24]
Hello

sin ..... | 0° |30°|45°|60°|90°|
...........| 0...| 1..| 2..|  3..| 4..|  write numbers
...........| 0...| 1..|√2.| √3 | 2..| take root square
...........| 0...|1/2|√2/2|√3/2|1| divide by 2
...........| 0...|1/2|√2/2|√3/2|1| .....
cos.....| 90°|60°|45°|30°| 0°|

sin (75°)
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cos 75°
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5 0
3 years ago
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