2x^2+20x=-38 divide both sides by 2
x^2+10x=-19, halve the linear coefficient, square it, than add that value to both sides of the equation, in this case add (10/2)^2=25...
x^2+10x+25=6 now the left side is a perfect square
(x+5)^2=6 take the square root of both sides
x+5=±√6 subtract 5 from both sides
x=-5±√6 (so answer c.)
Step-by-step explanation:
x intercept is when y = 0 and y intercept is when x = 0 hence, x intercept is : x = -56 hence (-56, 0) and y intercept is: 4y = -56 y = -14 hence (0, -14)
Topic: coordinate geometry
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Answer:
you forgot the question
Step-by-step explanation:
