All categories

1 year ago

I need help on solving these equations linear. Please helpppp

Mathematics

1 answer:

goldenfox [79]1 year ago

8 0

The solution of the first set of equations is x = 15 and y = 5 and the second is x = 14.25 and y = 7.75.

<h3>What is the equation?</h3>

There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.

More than one variable may be present inside a linear equation.

As per the given first system of equation,

2x - 4y = 10

x + 5y = 40 → 2x + 10y = 80

Subtract both

10y + 4y = 80 - 10

14y = 70

y = 5

And, x = 40 - 5(5) = 15

As per the given first system of equation,

3x - 5y = 4 and

-2x + 6y = 18 → -x + 3y = 9 → -3x + 9y = 27

Add both

-5y + 9y = 4 + 27

4y = 31

y = 7.75

x = (4 + 5(7.75))/3 = 14.25

Hence "The solution of the first set of equations is x = 15 and y = 5 and the second is x = 14.25 and y = 7.75".

For more about the equation,

brainly.com/question/10413253

#SPJ1

You might be interested in

What is the factored form of the function f(x)=x^3+8x^2+5x−50?

Inga [223]

Answer:

the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

Step-by-step explanation:

We need to factorise the function $f(x)=x^3+8x^2+5x-50$

If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50

Checking few numbers:

$f(1)=(1)^{3}+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^{3}+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0$

So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of $x^3+8x^2+5x-50$ by (x-2) to find other factors

The long division is shown in figure attached.

After long division we get: $x^2+10x+25$

The equation $x^2+10x+25$ can be further simplified as: (x+5)(x+5) or (x+5)^2

So, the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

3 0

3 years ago

#4 home do I find which one it is?

lina2011 [118]

$\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}$

$\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}$

for example, let's look at the first set

y+3x =5 or y = -3x+ 5
and y = -3x + 2
y = m + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution

8 0

4 years ago

What are the solutions to the following equation? x^2+8x+15=0

zubka84 [21]

Answer: It can be either one.

x=−3

x=−5

8 0

3 years ago

You have 90 minutes to complete atleast 18 chemistry and math problems. It takes 5 minutes to complet a chemistry problem and 4

Tcecarenko [31]

5C + 4M = 90.
C= chemistry
M=math

4 0

4 years ago

Read 2 more answers

The sum of 19.3 and a number is 30.4. Which equation can be used to solve the problem?

Viefleur [7K]

30.4 - 19.3 =x because you see if 19.3 plus a number equals 30.4 then that must mean if u do the oppisite you get the same number so u subtract either way the solution would be 11.1

3 0

3 years ago

Read 2 more answers