98 days = (98 ⁄ 7) weeks = 14 weeks
<span>Po = initial population = 5 </span>
<span>Ƭ = doubling time in weeks </span>
<span>t = elapsed time in weeks </span>
<span>P{t} = population after "t" weeks </span>
<span> P{t} = (Po)•2^(t ⁄ Ƭ) </span>
<span> P{t} = (Po)•2^(t ⁄ 4) </span>
<span> P{t} = 5•2^(t ⁄ 4) </span>
<span> P{14} = (5)•2^(14 ⁄ 4) … t = 14 weeks = 98 days </span>
<span> P{14} = 56 … population after 14 weeks</span>
The difference is 2003.
The formula for the sum of the first n even numbers is SE = n^{2} + n, (E standing for even).
The sum of the first n odd numbers is SO = n^{2}, (O standing for odd).
Knowing this, plug 2003 for n,
SE - SO= (2003^{2} + 2003) - (2003^{2}) = 2003
The difference is 2003.
A number that can be divided into two halves, i.e. into two equal parts is called an even number. Even numbers are exactly divisible by 2 which means the remainder will be 0.
Learn more about Even numbers here: brainly.com/question/251701
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Assuming you can't simply put the number inside a calculator: write the number as a fraction:
Find the prime factorization both numerator and denominator:
The square root halves the exponents, so the number becomes
Answer:
B
Step-by-step explanation:
