It would be
3.5 × 10⁻³ kg.
The decimal point must be moved 3 places to the right in order to have it behind the first non-zero digit; this gives us the exponent of 3, and since we are moving the decimal to the right, it is a negative exponent.
Answer:
20kg of 25% copper alloy
30kg of 60% copper alloy
Step-by-step explanation:
There are 2 kinds of metal, first metal(A) have 25% copper while the second metal(B) has 60% copper. The metalworker want to create 50kg of metal, which means the total weight of both metals is 50kg (A+B = 50). The metalworker also want the metal made of a 46% which is 23kg(0.25A + 0.6B = 0.46*50). From these sentences, we can derive 2 equations. We can solve this with substitution.
A+B = 50
A= 50-B
Let's put the first equation into the second.
0.25A + 0.6B = 0.46 *50
0.25(50-B) + 0.6B =23
12.5 - 0.25B + 0.6B =23
0.35B=23 -12.5
B= 10.5/ 0.35= 30
Then we can solve A
A= 50-B
A= 50-30
A=20
X basketball players who tried out for the team were chosen. They were distributed into 5 groups each. In one of the groups, 2 of the teammates left. How many players did that group have?
I'm sure you can word this even better.. I'm just in a rush.
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:
We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be 
and cost of y end-zone tickets would be 
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:
Upon substituting equation (1) in equation (2), we will get:
Therefore, 1100 field side tickets were sold.
Upon substituting in equation (1), we will get:
Therefore, 4500 end-zone tickets were sold.
1 foot is 12 inches
so 12 times 2
24
the answer is 24 inches
