Hello
f(x) = 2sin(x)
f(<span>π/6) = 1
f'(x) 2cos(x)
f'(</span>π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3)
The equation of this tangent line is : y= root(3)(x-π/6)+1
y = root(3)x+1 - π/6(root(x)) <span>in the form y=mx+b
m = root(3) and b = </span>1 - π/6(root(x))

8 0

3 years ago

The Khan family is constructing a backyard and needs your help with a design that will fit their budget. The backyard is in the

Nonamiya [84]

Answer:

2x1000=2000m

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If ln(x^2-x-1)=0 , then x= ?

Umnica [9.8K]

Answer:

x = -1 or 2

Step-by-step explanation:

Taking the antilog, you have the quadratic ...

x^2 -x -1 = 1

x^2 -x -2 = 0 . . . . subtract 1

(x -2)(x +1) = 0 . . . factor

The values of x that make these factors zero are the solutions to the equation.

x = 2 or x = -1

3 0

3 years ago