and surely you'd know what the roots are
(5 – 3x)4 – 2Please I need help. Show steps im so confused
1 answer:
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Answer:
A
Step-by-step explanation:
Calculate the slope of the given points with the point (- 2, 5 )
If the slope is - then the point is on the line
Calculate slope m using the slope formula
m =
with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)
m = =
= -
← point (6, - 1) is on the line
Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)
m = =
← point (2, 8) is not on the line
Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)
m = =
=
← point (- 5, 1) is not on the line
Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)
m = = -
← point (1, 1) is not on the line
Thus the point on the line is (6, - 1 ) → A
You can go through the effort of determining the zero of the function analytically and evaluating an analytic expression for the derivative at that point, or you can let a graphing calculator do that heavy lifting. Since the numbers have to be "nice" for your equation to have the desired form, it is easy to know what to round to in the event that is necessary (it isn't).
We find the positive zero-crossing at x=2, and the slope of the curve at that point to be 8. Thus the line will have slope -1/8 and can be written as
.. x +8y -2 = 0
We find the positive zero-crossing at x=2, and the slope of the curve at that point to be 8. Thus the line will have slope -1/8 and can be written as
.. x +8y -2 = 0