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IceJOKER [234]
3 years ago
9

12x times 5 equals 8x plus 26

Mathematics
1 answer:
kkurt [141]3 years ago
7 0
5(12x)=8x+26
60x=8x+26
52x=26
x=2
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The perimeter of the triangle is 13 inches. What is the length of the shortest side?
vlabodo [156]

Answer:

3 in

Step-by-step explanation:

Sum of all sides of ∆ = perimeter

Given that it has a perimeter of 13 in, and the following sides: (x - 5) in, x/2 in, and 6 in, therefore:

x - 5 + \frac{x}{2} + 6 = 13

Solve to find the value of x

\frac{2x - 10 + x + 12}{2} = 13

\frac{3x + 2}{2} = 13

Multiply both sides by 2

\frac{3x + 2}{2}*2 = 13*2

3x + 2 = 26

Subtract 2 from both sides

3x + 2 - 2 = 26 - 2

3x = 24

Divide both sides by 3

\frac{3x}{3} = \frac{24}{3}

x = 8

The shortest side = (x - 5) in

Plug in the value of x

= (8 - 5) in

= 3 in

6 0
3 years ago
Ayudaaaaa son progresiones aritméticas esas preguntas
kolezko [41]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Picture is in problem below. Will mark brainliest.
gladu [14]

Answer:

July 16

Step-by-step explanation:

The way to solve this problem is to look carefully at the question and then work through each statement in turn and see what we can deduce from it.

From the question we know that Albert has been told May, June, July or August.

Bernard has been told 14, 15, 16, 17, 18, or 19.

Albert: I don't know when Cheryl's birthday is, but I know that Bernard does not know too.

Bernard has been told the day of Cheryl's birthday. There are only two days, 18 and 19 that appear once on Cheryl's list. This means that Cheryl's birthday cannot be May 19th or June 18th as if it was then Bernard would know the answer.

Remember that Albert has been told a month and from the statement he knows that Bernard does not know the birthday. For Albert to be certain that Bernard does not know Cheryl's birthday, the month Albert had been told must not have been May or June.

Therefore Cheryl's birthday must fall in July or August.

Bernard: At first I don't know when Cheryl's birthday is, but I know now.

Based on the above Bernard has worked out that Cheryl's birthday is in July or August.

If Bernard now knows Cheryl's birthday the day he must have been told would be 15, 16 or 17. It cannot be 14 as this falls in both July and August and as such he wouldn't know Cheryl's birthday for certain.

Albert: Then I also know when Cheryl's birthday is.

Based on the above Albert has worked out that Cheryl's birthday is one of the following:

July 16

August 15

August 17

If Albert now knows for certain when Cheryl's birthday is he must have been told the month of July, as if it was August there would be two possible options.

Therefore the answer is July 16.

7 0
3 years ago
Read 2 more answers
Solve 3x+2y−z=2 2y+z=7 −2x−4z=−2 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=
Amanda [17]

Answer:

(-1, 3, 1)

x=-1, y=3, z=1.

Step-by-step explanation:

So we have the three equations:

3x+2y-z=2\\2y+z=7\\-2x-4z=-2

And we want to find the value of each variable.

To do so, look at the equations and try to think about what we can do to isolate one of the variables by itself.

We can see that both the second and equation has a variable and then the variable z.

In other words, we can solve for y in the second equation and x in the third equation and then substitute them in the first equation to isolate the variable z and then solve for z. With that, we can then easily arrive at our solution.

Therefore, solve for y in the second equation:

2y+z=7

Subtract z from both sides. The zs on the left side cancels:

(2y+z)-z=(7)-z\\2y=7-z

Now, divide both sides by 2. The 2s on the left cancel and we've isolated the y variable:

\frac{(2y)}{2} = \frac{(7-z)}{2}\\y=\frac{(7-z)}{2}

Now, do the same for the third equation. Isolate the x variable:

-2x-4z=-2

First, divide everything by -2 to make things simpler:

\frac{(-2x-4z)}{-2}=\frac{(-2)}{-2}\\  x+2z=1

Now, subtract 2z from both sides to isolate the x variable:

(x+2z)-2z=1-2z\\x=1-2z

We have isolated the x and y variables. They are:

y=\frac{(7-z)}{2}\\x=1-2z

Now, we can substitute them back into the first equation. Therefore:

3x+2y-z=2\\3(1-2z)+2(\frac{7-z}{2})-z=2

Distribute the first and second terms. The second term cancels out:

3(1)-3(2z)+(7-z)-z=2\\3-6z+7-z-z=2

Combine like terms:

-6z-z-z+3+7=2\\-8z+10=2\\

Subtract 10 from both sides:

(-8z+10)-10=2-10\\-8z=-8

Divide both sides by -8:

z=1

Now that we've determined that z=1, plug it back into the isolated second and third equations:

Second equation:

y=\frac{(7-z)}{2}\\y=(7-1)/2\\y=(6)/2=3

Third equation:

x=1-2z\\x=1-2(1)\\x=1-2=-1

Therefore, our answer is (-1, 3, 1)

7 0
4 years ago
Read 2 more answers
Is 8 yard, 9 yards, and 12 yards right triangle
Andrews [41]

Answer:

No

Step-by-step explanation:

you can check with the pythagorean theory

8^{2}+9^{2} =12^{2}

64 + 81 = 144

145 = 144

this is not true, therefore those side lengths do not make a right triangle.

4 0
3 years ago
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