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egoroff_w [7]
1 year ago
14

the average number of chocolate chips in a particular brand of chocolate chip chewy cookie is 19. the standard deviation is 2.6.

assuming that the number of chocolate chips per cookie is normally distributed, what percent of cookies would have between 13.8 and 24.2 chips?
Mathematics
1 answer:
zzz [600]1 year ago
5 0

The probability illustrated shows that the

percent of cookies would have between 13.8 and 24.2 chips is 95.44%.

<h3>How to calculate the probability?</h3>

It is important to note that the requirement to solve the probability between z-values is to know that the probability between the z-values is the difference between the probability of the greatest z-value and the lowest z-value.

This will be illustrated thus:

Z value for 13.8, z =(13.8-19)/2.6 =-2

Z value for 24.2, z =(24.2-19)/2.6 = 2

P( 13.8<x<24.2) =P(-2<z<2)

=P( z <2 –P(z < -2)

=0.9772 -0.0228

=0.9544

= 95.44%

The percent is 95.44%.

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

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