Answer:
A
Step-by-step explanation:
To find the best equation, we simply substitute the values of a, b, and c into the given equations.
a = 21
b = 5
c = 36
Small one: 18 and 1-thirds yards² Large one: 43.5 yards²
Step-by-step explanation:
Area of rectangle= base*height
Large one: base = 6, height= 7.25 (7 and 1-fourth)
Area= 43.5yards²
Small one: base = 3(2/3 or 2-thirds), height= 5
change the mixed fraction 3(2/3) to 11/3
area= 11/3 * 5 = 55/3
change to mixed fraction which = 18(1/3)
<span>(box volume/ball volume) * packing density = # mables that fit in box
max packing density is pi/3*sqrt(2) for spheres, according to the Kepler conjecture, so if ball volume is b,
(4.5 * 4.5 * 7.5 / b) * (pi/3*sqrt(2)) = 160
151.875 / b * (pi/3*sqrt(2)) = 160
151.875 * pi / b * 3 * sqrt(2) = 160
50.625 * pi / b * sqrt(2) = 160
10.125 * pi / 32 * sqrt(2) = b
b ~ 0.7
For a tin cylinder of 4.5 diameter, the volume is (4.5/2)^2 * pi * h. Using the formula again,
(box volume/ball volume) * packing density = # mables
(5.0625 * pi * h / (10.125 * pi / 32 * sqrt(2)) * (pi/3*sqrt(2)) = 160
(5.0625 * pi * h * 32 * sqrt(2) / 10.125 * pi) * (pi/3*sqrt(2)) = 160
5.0625 * h * 32 * sqrt(2) / 10.125 * (pi/3*sqrt(2)) = 160
162 * h * sqrt(2) * pi / 10.125 * 3 * sqrt(2) = 160
54 * h * pi / 10.125 = 160
54 * h * pi = 1620
h * pi = 30
h = 30/pi
h ~ 9.55
So if the marbles are of equal size, and both the box and cylinder are packed as tightly as possible, the cylinder would have to be 9.55 units tall.</span>
