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1 year ago

Please help with this i will attach photo of figure

Mathematics

1 answer:

Zigmanuir [339]1 year ago

8 0

The variable I=f(w) represents the number of individuals (in thousands) infected w weeks after the epidemic begins.

The value of I=f(2) represents the number of individuals in thousandas infected 2 weeks after the beginning of the epidemic.

From the graph, where I=8, we can conclude that there are 8,000 infected people after 2 weeks of the beginning of the epidemic.

Answer:

f(2) = 8

Means 8,000 people are infected after 2 weeks of the beginning of the epidemic.

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Can someone show me what is 5% of 34 and show me how to breakdown the equation?

vesna_86 [32]

The answer for this problem is 1.7 I think I’m not sure

4 0

3 years ago

Find the slope(6,8) and (9,10)

USPshnik [31]

name the points

a=(x1,y1) b=(x2,y2)

a=(6,8) b=(9,10)

use the slope formula

$m=\frac{y2-y1}{x2-x1}$

replace

$\begin{gathered} m=\frac{10-8}{9-6} \\ m=\frac{2}{3} \end{gathered}$

answer= The slope is equal to 2/3

a=(9,10) b=(6,8)

using the formula

$\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{8-10}{6-9} \\ m=\frac{-2}{-3}=\frac{2}{3} \end{gathered}$

slope will also be 2/3

5 0

1 year ago

uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m

Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0

3 years ago

Can someone help me I’ll Mark brainliest I been struggling with this one :(

mariarad [96]

Answer:

Step-by-step explanation:

5 0

2 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.

6 0

1 year ago

Read 2 more answers