X^2+7x-8>0 eliminating denominator
Factoring (x+8)(x-1) must be positive so
Case 1 both positive is x>-8 and x>1. For both to occur x>1
Case 2 both are negative (x+8)<0 and (x-1)<0 so x<-8 and x<1. For both to occur x<-8
Therefore x<-8 or x>1
Answer:
20 N
Step-by-step explanation:
Since, both the forces are acting in opposite directions.
Therefore,
If you were to convert 3/4 and 4/5 to have the same denominator it would be 15/20 and 16/20.
Now we compare. This should be easy...
Its 4/5 or 16/20.
The answer is C: x < -2
The fact that it is less than -2 is shown by the open circle on -2, and the arrow pointing to the left. An open circle means that the number cannot be included (which is why it can't be "less than or equal to," but instead is just "less than."), and the line pointing to the left means that your variable is specifically less than the number circled.
It’s combining like terms so it would be.
X-2x-8=
-x-8
