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Mrac [35]
3 years ago
9

The area of a trapezoid is 144cm2. The height is 16cm and the length of one of the parallel sides is 6cm. Find the length of the

second parallel side. Express your answer as a simplified fraction or a decimal rounded to two places.
Mathematics
2 answers:
Lemur [1.5K]3 years ago
4 0

Step-by-step explanation:

hope this will help you have a great day!

Ganezh [65]3 years ago
4 0

Answer:

0.12

Step-by-step explanation:

I don't know how to explain it to you, but I hope you'll understand from the picture. hope it helps.

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The J.R. Ryland Computer Company is considering a plant expansion to enable the company to begin production of a new computer pr
Solnce55 [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Medium-Scale Large-Scale

Expansion Profit Expansion Profit

x f(x) y f(y)

Low 50 0.2 0 0.2

Demand Medium 150 0.5 100 0.5

High 200 0.3 300 0.3

a. Compute the expected value for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of maximizing the expected profit?

Expected value for medium scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(50 * 0.2) + (150 * 0.5) + (200 * 0.3)]

= 145

Expected value for Large scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(0 * 0.2) + (100 * 0.5) + (300 * 0.3)]

= 140

Medium scale expansion profit is preferred as it has the highest expected value.

b. Compute the variance for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of minimizing the risk or uncertainty?

Variance (V) = Σ(X - E)² * f(x):

Variance for medium scale expansion profit :

V = [((50-145)^2 * 0.2) + ((150-145)^2 * 0.5) + ((200-145)^2 * 0.3) = 2725

Variance for Large scale expansion profit :

V = [((0-140)^2 * 0.2) + ((100-140)^2 * 0.5) + ((300-140)^2 * 0.3) = 12400

Smaller variance is required to minimize risk, Hence, choose the medium scale expansion profit.

3 0
3 years ago
Simplify the expresion <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B3.%20%5Csqrt%5B4%5D%7B432%7D%20%7D%20" id="TexF
Bond [772]
\sqrt[4]{3. \sqrt[4]{432}}
= \sqrt[4]{3. \sqrt[4]{2^4.3^3} }
= \sqrt[4]{3.2.3^\frac{3}{4}}
= 3^\frac{1}{4}.2^\frac{1}{4}.3^\frac{3}{16}
= 3^\frac{7}{16}.2^\frac{1}{4}



6 0
3 years ago
What is the value of x?<br><br> 20<br> 35<br> 60<br> 70
fenix001 [56]

The given angles are =

(x+40)° and 3x°

As the given angles are opposite to each other on the intersecting lines, so they are vertical angles. These are congruent or equal.

So, x+40=3x

2x=40

x=20

Hence x = 20°

The given angles are =

(x+40) = 20+40 =60°

3x = 3*20 =60°


5 0
3 years ago
Find the coordinate of the midpoint of the segment formed by the given points: (7, 11) and (3, -5)
sveta [45]

Answer:

MP = (5,3)

Step-by-step explanation:

MP= (\frac{x_1+x_2}{2}) (\frac{y_1+y_2}{2} )\\MP= (\frac{7+3}{2}) (\frac{11+-5}{2} )\\MP= (\frac{10}{2}) (\frac{6}{2} )\\MP= (5,3)

8 0
3 years ago
How do I work this. I have no idea what to do
anastassius [24]

Answer: I think it’s 9.2? Idk

Step-by-step explanation:

6 0
3 years ago
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