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Ludmilka [50]
2 years ago
8

Subtract.(6t² - 5t) - (2t² - 9t + 6)

Mathematics
1 answer:
Tcecarenko [31]2 years ago
8 0

We are given the following equation:

\mleft(6t^{2}-5t\mright)-(2t^{2}-9t+6​)

Now we use the distributive property for the parenthesis:

6t^{2}-5t-2t^{2}+9t-6​

Now we associate like terms, that is, terms that have the same variable elevated to the same exponent:

(6t^2-2t^2)+(-5t+9t)-6

Now we add like terms:

4t^2+4t-6

Since this expression can't be simplified any further then this is the final answer.

You might be interested in
A. 37<br> B. 38<br> C. 39<br> D. 40
Dvinal [7]

Hello ^w^

I believe the answer you are looking for is A

I found this answer by adding up the lengths of all the sides.

S -> T = 8

S -> R = 7

Q -> R = 6

P -> Q = 6

P -> T = 10

10 + 6 + 6 + 7 + 8 ->  37

A -> 37

If I am incorrect, please inform me.

Have a good day!

4 0
3 years ago
Claudia spends $2.15 a day for lunch. Her cafeteria lunch account has a balance of $48.00. Which equation can be used to determi
andreev551 [17]

Answer:

d≤48/2.15

Step-by-step explanation:

Step one:

Given data

Claudia spends $2.15 a day for lunch.

We are told that her balance is  $48.00

let the number of days be d

Step two:

The maximum number of days she can eat is given as

d≤48/2.15

d≤22.33 days

7 0
3 years ago
What is the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12)?
ki77a [65]

The general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

<h3>What is the vertex form of a quadratic equation?</h3>

Vertex form of the quadratic equation is used to find the coordinate of vertex points at which it crosses its symmetry.

The standard equation of the vertex form of quadratic is given as,

y=a(x-h)^2+k

Here, (h, k) is the vertex point.

The vertex of quadratic at (2, 3) and passing through the point (5, 12). Put the value of vertex point in the above equation,

y=a(x-2)^2+3

As the quadratic passes through the point (5, 12). Thus, put the value of this point,

12=a(5-2)^2+3\\12-3=a(3)^2\\9=a\times9\\a=\dfrac{9}{9}\\a=1

Put the value of <em>a</em> in the above expression,

y=1(x-2)^2+3\\y=(x-2)^2+3\\y=x^2-4x+4+3\\y=x^2-4x+7

Thus, the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

Learn more about the vertex form here;

brainly.com/question/17987697

#SPJ1

4 0
3 years ago
Helppppppppppppp pleaseeeeeeeeeeeeeeee
strojnjashka [21]

Answer:

The answer would be b, 8:13

4 0
3 years ago
SOME ONEEE PLZZ HELPP MEEEE
Dominik [7]

Answer:

2.5

Step-by-step explanation:

The minimum value is the minimum y-value a function includes. In this case, since you can see the function is periodic (it repeats itself <em>periodically</em>, hence periodic) and the smallest y-value the function encounters is 2.5 (doesn't go below this value), the minimum y-value is 2.5. I hope this made sense. If not, feel free to let me know.

6 0
3 years ago
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