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Nadusha1986 [10]
1 year ago
7

X-y=-2y=-2x-3how to solve this question

Mathematics
1 answer:
Karo-lina-s [1.5K]1 year ago
4 0
\begin{gathered} \text{The equation is,} \\ x-y=-2\ldots\text{.}(1) \\ y=-2x-3\ldots(2) \\ \text{substitute the value of y in the equation (1).} \\ x-(-2x-3)=-2 \\ x+2x+3=-2 \\ 3x=-5 \\ x=-\frac{5}{3} \\ \text{Now, put the value of x in equation (2).} \\ y=-2\times(-\frac{5}{3})-3 \\ y=\frac{10}{3}-3 \\ y=\frac{1}{3} \\ So,\text{ the solution is (-5/3, 1/3)} \end{gathered}

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4 years ago
If (x-y)^2=71 and x^2+y^2=59 what is the value of xy?
Lena [83]
Solve the equations
first one
take the sqrt of both sides
x-y=√71
add y to both sides
x=y+√71
sub y+√71 for x in other part


(y+√71)²+y²=59
y²+2y√71+71+y²=59
2y²+2y√71+71=59
minus 59 both sides
2y²+2y√71+12=0
factor out 2
2(y²+y√71+6)=0
use quadratic equation or something
y=\frac{- \sqrt{71}- \sqrt{47}  }{2} and \frac{- \sqrt{71}+ \sqrt{47}  }{2}

sub those for x

x=y+√71
note: √71=(2√71)/2

x=\frac{- \sqrt{71}- \sqrt{47}  +2\sqrt{71}}{2} ,\frac{\sqrt{71}- \sqrt{47}}{2}
or
x=\frac{- \sqrt{71}+ \sqrt{47}  +2\sqrt{71}}{2} ,\frac{\sqrt{71}+ \sqrt{47}}{2}

xy=\frac{\sqrt{71}- \sqrt{47}}{2}  times \frac{-\sqrt{71}- \sqrt{47}}{2} or \frac{\sqrt{71}+ \sqrt{47}}{2}  times \frac{-\sqrt{71}+ \sqrt{47}}{2}

the result is -6 both times

xy=-6
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4 years ago
-u/5=-27 help pls due today
ElenaW [278]

Answer:

u = 135

hoped i helped u

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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Which of the following is the value of a when the function f(x)=3 [x]written in the standard form of an absolute value function?

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Step-by-step explanation:

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