Question

Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0

Answer 1

• The value of the discriminant ,D= -16

,

• The solution to the quadratic equation is

$x=\frac{1+2i}{5}\text{ or }\frac{1-2i}{5}$

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

,

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

$x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}$

Note that:

√-1 = i

$x=\frac{2\pm\sqrt[]{16\times-1}}{10}$

$x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}$$x=\frac{2\pm4i}{10}$$x=\frac{2}{10}\pm\frac{4i}{10}$$x=\frac{1}{5}\pm\frac{2}{5}i$$x=\frac{1\pm2i}{5}$

That is;

$\text{Either x=}\frac{1+2i}{5}\text{ or x=}\frac{1-2i}{5}$