Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
Answer:
-d-20
Step-by-step explanation:
Hope this helps!
Answer:
wheres the table can you please provide one
Step-by-step explanation:
Answer:
5x³ - 2x²
Step-by-step explanation:
Step 1: Write out expression
4x³ - x² + 4x + x³ - x² - 4x
Step 2: Combine like terms (x³)
5x³ - x² + 4x - x² - 4x
Step 3: Combine like terms (x²)
5x³ - 2x² + 4x - 4x
Step 4: Combine like terms (x)
5x³ - 2x²
Tyler concludes that 5x² will always have a larger output for the same value of x.
<u>Look at the graph below and the table given</u>
Take a random value: x = 0
Here, 1 > 0, making 2^x > 5x²
Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.
Disagree with Tyler's point.
