Answer:
He goes 4 miles
Step-by-step explanation:
Answer:
bisect each other.
Step-by-step explanation:
The midpoints are the same point, so the diagonals bisect each other.
__
<em>More elaboration on a proof</em>
The alternate interior angles formed by diagonals and the sides of the triangle are congruent, so the (point-to-point) triangles formed by the crossing diagonals are congruent ASA. Since the sides of those triangles are congruent, the diagonals meet at their midpoints. That is, the diagonals bisect each other.
Answer:
the domain is x and the range is 1
Step-by-step explanation:
Believe it or not, :), the width of the ribbon needs to be known to get the right answer. If the ribbon had an infinitely small width the ribbon needed would just be the perimeter.
P=2(L+W)
P=2(12+15)
P=54 in
However an infinitely small width is not something that has any practical application. For example, if the width of the ribbon were 1/2 in.
P=2((L+1)+W)
P=2(16+12)
P=56 in So the perimeter increased by 2 in when the ribbon was only 1/2 in wide.
The "infinitely small" width and the perimeter of 54 in is only a decent approximation if the ribbon were a very thin string.
Answer:
creo que sería 54 por actitud de :72-1 1?? por eso sería esta cosa esxtactamente espero que te allá ayudado
