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Damm [24]
3 years ago
15

What is the difference in mean solar time between 30 N 75 W and 30 N 90 W​

Chemistry
1 answer:
ratelena [41]3 years ago
5 0

Answer:

Every 15 degrees is an hour

Explanation:

What is the time difference in mean solar time between 30° N 75° W and 30° N 90° W?

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Why is the cell membrane essential for cell homeostasis? A. To create food for the body B. To make energy for other tissues C. P
jek_recluse [69]

Answer: it C

Explanation: Because is the only that makes sense and the only one that seems right

3 0
4 years ago
If you are administering an oral acetaminophen dose of 320. mg from a bottle at a concentration of 32.0 mg/ml , how many millili
aliina [53]
The  number  of  milliliters of  the   solution  that you  need  to  give  to  the  patient  is  calculated  as  follows

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 =( 320mg  x 1 ml) /32mg=  10ml
4 0
4 years ago
which SAE standard must be referred to on the label of approved HFC-134a refrigerant recycling machines?
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Answer is: S<span>AE standard that must be referred to on the label of approved HFC-134a refrigerant recycling machines are </span>J1770 and J2788.
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8 0
3 years ago
What are the amplitude's for both waves A and B?
Bad White [126]

Answer:

Wave A= 20m

Wave B= 30m

Explanation:

The amplitude of a wave is the maximum displacement (or height) from its equillibrum position.

The equilibrium position is at 0 meters for both waves.

Thus, amplitude of wave A= 20m

Amplitude of wave B= 30m

5 0
3 years ago
Calculate ΔG∘rxn for the following reaction:4CO(g)+2NO2(g)→4CO2(g)+N2(g).Use the following reactions and given ΔG∘rxn values:A)
mihalych1998 [28]

Answer : The   value of \Delta G^o_{rxn} for the reaction is -1131.4 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The given main reaction is,

4CO(g)+2NO_2(g)\rightarrow 4CO_2(g)+N_2(g)    \Delta G^o_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) 2NO(g)+O_2(g)\rightarrow 2NO_2(g)     \Delta G^o_1=-72.6kJ

(2) 2CO(g)+O_2(g)\rightarrow 2CO_2(g)     \Delta G^o_2=-514.4kJ

(3) \frac{1}{2}O_2(g)+\frac{1}{2}N_2(g)\rightarrow NO(g)     \Delta G^o_3=87.6kJ

Now we will reverse the reaction 1, multiply the reaction 2 by 2, reverse and half the reaction 3 and then adding all the equations, we get :

(1) 2NO_2(g)\rightarrow 2NO(g)+O_2(g)     \Delta G^o_1=72.6kJ

(2) 4CO(g)+2O_2(g)\rightarrow 4CO_2(g)     \Delta G^o_2=2\times (-514.4kJ)=-1028.8kJ

(3) 2NO(g)\rightarrow O_2(g)+N_2(g)     \Delta G^o_3=-2\times 87.6kJ=-175.2kJ

The expression for \Delta G^o_{rxn} will be,

\Delta G^o_{rxn}=\Delta G^o_{1}+\Delta G^o_{2}+\Delta G^o_{3}

\Delta G^o_{rxn}=(72.6kJ)+(-1028.8kJ)+(-175.2kJ)

\Delta G^o_{rxn}=-1131.4kJ

Therefore, the value of \Delta G^o_{rxn} for the reaction is -1131.4 kJ

3 0
4 years ago
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