Question

sam records the mass of his evaporating dish as 8.365 g. he records the mass of the evaporating dish and the sample of hydrate as 18.597 g. after heating the sample in the evaporating dish to constant weight, the mass of them combined is 13.735 g. how many moles of water were removed from the sample by the heating process? report your answer with three digits after the decimal.

Answer 1

0.2701 moles of water were evaporated from the sample by the heating process

Mass of evaporating dish = 8.365 g

mass of dish + hydrate = 18.597 g

mass of hydrate =  (mass of dish + hydrate) - mass of dish

hydrate = 18.597 - 8.365 = 10.232 g

Mass of dehydrated material = (mass of dish + dehydrate ) - mass of dish

dehydrated material = 18.735 - 8.365 = 5.37 g

Mass of water evaporated = hydrate - dehydrate

mass of water = 10.232 - 5.37 = 4.862 g

Molar mass of water  = 18 gm/mol

no. of moles of water evaporated = mass / molecular mass

moles = 4.862/18 = 0.2701 moles

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