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Lelechka [254]
3 years ago
11

How much does a gold AU bar weigh and how much is it worth

Chemistry
1 answer:
Grace [21]3 years ago
8 0
It weighs 12.4 kg and is costs $1266.90
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A student makes a compound of sulfur and oxygen. She uses 5.00 g of sulfur and 4.99 g of oxygen, and all of the elemental substa
victus00 [196]
First, we apply the law of conservation of mass which states that the total mass in a system remains constant.
Therefore, there must be 5.00 g of sulfur and 4.99 g of oxygen in the product. Now, we determine the mass percentage using:

Mass % = (mass of sulfur x 100) / total mass of compound

Mass % = (5 * 100) / (5 + 4.99)

Mass % = 50.05%

The product contains 50.05% sulfur by mass.
7 0
4 years ago
How many grams of a 23.4% by mass naf solution is needed if you want to have 1.33 moles of naf?
jenyasd209 [6]
Percentage by mass is the mass of NaF present in 100 g of the solution.
the percentage by mass of NaF is 23.4 %
this means that in 100 g of solution, mass of NaF present is 23.4 g
the number of moles of NaF present - 1.33 mol
mass of NaF - 1.33 mol x 42 g/mol = 55.9 g
when there's 23.4 g of NaF - mass of solution is 100 g
therefore when there's 55.9 g of NaF - mass of solution is 100 / 23.4 x 55.9 
= 239 g
mass of solution required is 239 g
6 0
4 years ago
Which of the following an inorganic compound?
oksano4ka [1.4K]
An organic compound is one which consists of a chain of carbon atoms with other atoms bonded to the chain.

Pentane has 5 carbon atoms with surrounding hydrogens.
glucose is a chain of 6 carbon atoms
butane is similar to pentane

water has no carbon atoms, and the central atom is oxygen ---> therefore it is inorganic!
8 0
4 years ago
How many moles are contained in a 4.67-l sample of gas at 30 c and 199 kpa?
valentina_108 [34]

Using ideal gas equation,

PV=nRT

P=199 kpa

V=4.67 L

T=30+273K= 303K

n= number of moles of gas

R=8.321 L·kPa·K-1·mol-1

So using ideal gas equation,

n=PV/RT

=199*4.67/8.321*303\

=0.37 mol

3 0
4 years ago
Read 2 more answers
What is the molarity of a solution made by mixing 75.0 mL of 3.00 M NH₄OH with enough water to give 250. mL of solution?
enyata [817]

Answer:

Mass 1=3M

Mass 2=?

Volume1=75mL

Volume2=250mL

By using molarity formula:

<u>mass1*volume 1=mass2*volume 2</u>

3M*75=mass2*250

mass2=225/250

mass2:0.9M

<h3>the molarity of a solution is 0.9M.</h3>
7 0
3 years ago
Read 2 more answers
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