First, we apply the law of conservation of mass which states that the total mass in a system remains constant.
Therefore, there must be 5.00 g of sulfur and 4.99 g of oxygen in the product. Now, we determine the mass percentage using:
Mass % = (mass of sulfur x 100) / total mass of compound
Mass % = (5 * 100) / (5 + 4.99)
Mass % = 50.05%
The product contains 50.05% sulfur by mass.
Percentage by mass is the mass of NaF present in 100 g of the solution.
the percentage by mass of NaF is 23.4 %
this means that in 100 g of solution, mass of NaF present is 23.4 g
the number of moles of NaF present - 1.33 mol
mass of NaF - 1.33 mol x 42 g/mol = 55.9 g
when there's 23.4 g of NaF - mass of solution is 100 g
therefore when there's 55.9 g of NaF - mass of solution is 100 / 23.4 x 55.9
= 239 g
mass of solution required is 239 g
An organic compound is one which consists of a chain of carbon atoms with other atoms bonded to the chain.
Pentane has 5 carbon atoms with surrounding hydrogens.
glucose is a chain of 6 carbon atoms
butane is similar to pentane
water has no carbon atoms, and the central atom is oxygen ---> therefore it is inorganic!
Using ideal gas equation,
PV=nRT
P=199 kpa
V=4.67 L
T=30+273K= 303K
n= number of moles of gas
R=8.321 L·kPa·K-1·mol-1
So using ideal gas equation,
n=PV/RT
=199*4.67/8.321*303\
=0.37 mol
Answer:
Mass 1=3M
Mass 2=?
Volume1=75mL
Volume2=250mL
By using molarity formula:
<u>mass1*volume 1=mass2*volume 2</u>
3M*75=mass2*250
mass2=225/250
mass2:0.9M
<h3>the molarity of a solution is 0.9M.</h3>
