Let the hydrated compound be CaSO4.xH2O
mass of the caso4= 43.63g /(40+32+64+18x)* (40+32+64)= 36.45g
136+18x=( 43.63*136) / 36.45= 162.78
18x = 162.78- 136= 26.8
x = 1.48 = 1.5
Formula of hydrate = CaSO4.1.5H2O = 2CaSo4. 3H2O
Answer:
94.58 g of
Explanation:
For this question we have to start with the reaction:
Now, we can balance the reaction:
We have the amount of and the amount of
. Therefore we have to find the limiting reactive, for this, we have to follow a few steps.
1) Find the moles of each reactive, using the molar mass of each compound (
).
2) Divide by the coefficient of each compound in the balanced reaction ("2" for and "1" for ).
<u>Find the moles of each reactive</u>
<u>Divide by the coefficient</u>
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The smallest values are for , so hydrogen is the limiting reagent. Now, we can do the calculation for the amount of water:
We have to remember that the molar ratio between and is 2:2 and the molar mass of is 18 g/mol.
R = 1.3 A° = 1.3 × 10^(-10) m
V = 9.20277208×10^(−30) m.
The answer is A. Tessa does more work than Cindy because she weighs more. The work being done is determined by both force and distance. When distance is same, the bigger force, the more work.
Answer:
The electronic configuration of Na is b