All categories

2 years ago

What are some ways ou can represent a proportional relationship?equations ,or graphs,or tables ,or can be all of them

Mathematics

1 answer:

Nataly [62]2 years ago

6 0

Proportional relationship

We know a proportional relationship is when one of the variable is obtained by multiplying the other variable by a constant number.

For example, in an equation it can be represented:

<em />

In a table, we can represent it by

<em />

In a graph,

Answer: all of them

You might be interested in

Steve buys a new coat from Don's clothing store. Don buys coats from Mary's factory, and Mary buys her material from Sean's mill

mihalych1998 [28]

The answer you seek is interdependance

5 0

4 years ago

Read 2 more answers

the lengths of the sides of a triangle are in the extened ratio 3:6:8. The triangle's perimeter is 520cm. What are the lengths o

Kaylis [27]

The three lengths are 3x, 6x, 8x.

The perimeter of a triangle is the sum of all lengths:
3x + 6x + 8x = 520.

Solving for x,
17x = 520
x = 30.59 cm

So the three lengths are
3(30.59) = 91.77 cm
6(30.59) = 183.54 cm
8(30.59) = 244.72 cm

4 0

3 years ago

The circumference of a sphere was measured to be 90 cm with a possible error of 0.5 cm.

Akimi4 [234]

Answer:

Error in the sphere's surface: 29 $cm^2$ and relative error in surface measure: 0.011

Error in the sphere's volume: 205 $cm^3$ and relative error in the volume measure: 0.017

Step-by-step explanation:

(a)

The measured length (l) of the circumference is 90 cm with an error of 0.5 cm, that is:

$l=2\,\pi\,R=90\,cm\\R=\frac{90}{2\,\pi} \,cm=\frac{45}{\pi} \,cm=14.3239\,\,cm$

and with regards to the error:

$dl=0.5 \, cm\\dl=2\,\pi\,dR\\dR=\frac{dl}{2\,\pi} =\frac{1}{4\,\pi} cm = 0.0796\,cm$

then when we use the formula for the sphere's surface, we get:

$S=4\,\pi\,R^2\\dS=4\,\pi\,2\,R\,(dR)\\dS=8\,\,\pi\.(\frac{45}{\pi} \,\,cm)\,(\frac{1}{4\pi}\,cm) =\frac{90}{\pi} \,\,cm^2\approx \,29\,cm^2$

Then the relative error in the surface is:

$\frac{dS}{S} =\frac{90/\pi}{4\,\pi\,R^2} =\frac{1}{90} =0.011$

(b)

Use the formula for the volume of the sphere:

$V=\frac{4\,\pi}{3} R^3\\dV=\frac{4\,\pi}{3}\,3\,R^2\,(dR)=4\,\pi\,R^2\,(\frac{1}{4\pi}) \,cm=(\frac{45}{\pi})^2 \,\,cm^3\approx 205\,\,cm^3$

Then the relative error in the volume is:

$\frac{dV}{V} =\frac{205}{12310.5} \approx 0.017$

3 0

3 years ago

Does the size of the square unit that is used to cover a shape make a difference in

Crazy boy [7]

Answer:

No it does not

Step-by-step explanation:

5 0

3 years ago

Add. (6x2 – 2x) + (5x – 7)

11Alexandr11 [23.1K]

Answer:

Thats going to be 12x

Step-by-step explanation:

8 0

3 years ago