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3 years ago

4n g(n) = 3n² +41 g h(n) = 2n - 5 = Find (goh)(4)

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

3 0

g * h = 6n squared + 77

6*4^2 + 77 = 125

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Help pleasee I don’t get it

max2010maxim [7]

Answer:

no they're not congruent

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3 years ago

Factorise fully -x - 8

natta225 [31]

Answer:

x = -8 please mark brainliest

Step-by-step explanation:

Pull out like factors :

-x - 8 = -1 • (x + 8)

Equation at the end of step 1 :

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : -x-8 = 0

Add 8 to both sides of the equation :

-x = 8

Multiply both sides of the equation by (-1) : x = -8

3 0

3 years ago

Please help BRAINLIEST

Veseljchak [2.6K]

A) (1,3)
B) (-4,0)
C) (-6,0)
D) (2,4)
E)cant do E

I don’t know if there are other questions because I can only see up to E.
I hope this helped though and please mark as brainliest

7 0

3 years ago

Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

Hence, (-1,5) is on the graph

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

(1,0) is not on the graph because g(x) is not equal to 0

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

Hence, $(3, \frac{1}{125})$ is on the graph

D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

Hence, $(-2, \frac{1}{25})$ is not on the graph

8 0

4 years ago

The circumference of a circle is 69.08 yards. What is the circle's radius? Use 3.14

yawa3891 [41]

Answer:

r = 11

Step-by-step explanation:

C = 2πr

69.08 = 2(3.14)r

69.08 = 6.28r

r = 69.08/6.28

r = 11

4 0

3 years ago