Question

Use the first and last data points to find the slope intercept equation of a trend line.

Answer 1

Answer:

y = $\frac{16}{3}x-79$

Step-by-step explanation:

From the given table,

Two points are (1, 15) and (7, 47)

If the two points $(x_1,y_1)$ and $(x_2,y_2)$ are lying on a line then slope 'm' of the line will be,

m = $\frac{y_2-y_1}{x_2-x_1}$

   = $\frac{47-15}{7-1}$

   = $\frac{32}{6}$

   = $\frac{16}{3}$

Let the equation of a line passing through (h, k) is,

y - h = m(x - k)

If the line passes through (1, 15)

y - 1 = $\frac{16}{3}(x-15)$

y = $\frac{16}{3}x-\frac{16}{3}(15)+1$

y = $\frac{16}{3}x-80+1$

y = $\frac{16}{3}x-79$