We are asked to express cos^ 3 x in terms of powers of trigonometric functions not greater than 1
cos ^ 3 x is equal to cos x * cos^2 x.
<span>cos^2 x = 1 - sin^2 x.
</span>sin^2 x = (1 - cos 2x) /2
the answer is cos ^ 3 x = cos x * (1 - <span> (1 - cos 2x) /2 )</span>
Answer:
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Answer:
y+1=5/2(x+2)
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-6-(-1))/(-4-(-2))
m=(-6+1)/(-4+2)
m=-5/-2
m=5/2
y-y1=m(x-x1)
y-(-1)=5/2(x-(-2))
y+1=5/2(x+2)
Answer:
Step-by-step explanation:
First do your x2-x1/y2-y1 to find slope, which is 0-3/7-13 = -3/-6 = 1/2
Then plug into point slope form (choose either point)
(y-13) = 1/2(x-0)
OR
(y-7) = 1/2(x-3)
<span>(5a^2-4)*(25a^4+20a^2+16) is your answer</span>
