1 year ago

How to find the area of a circle

Mathematics

1 answer:

Vlad1618 [11]1 year ago

6 0

Area of a circe = Pi x radius^2

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(-9x-3)+6<93 help me out plz

Lunna [17]

Answer:

x>-10

Step-by-step explanation:

(-9x-3) + 6 < 93

-9x-3+6 < 93

-9x + 3 < 93

-9x < 93-3 (subtracting 3 both sides)

Dividing by -9 both sides

x > 90/-9 ( switch the sign because dividing by a negative number)

x> -10 Answer

Hope this helps!

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2 years ago

Por favor alguien me puede ayudar con esto

Gnoma [55]

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3 years ago

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2 years ago

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73

faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]

Therefore,

CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})$

Thus,

Lower limit of CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}})$

Lower limit of CI = $(98.3 - \frac{2.62\times0.73}{\sqrt{103}})$

Lower limit of CI = 98.11

and,

Upper limit of CI = $(Mean + \frac{t\times\sigma}{\sqrt{n}})$

Upper limit of CI = $(98.3 + \frac{2.62\times0.73}{\sqrt{103}})$

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F

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2 years ago

Order these from least to greatest<br> 9, 3, π

ale4655 [162]

Answer:

3 pi 9

Step-by-step explanation:

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2 years ago