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Tom [10]
3 years ago
10

(please zoom / zoom out if needed to see question. (: )

Mathematics
1 answer:
eduard3 years ago
3 0
You can find the area of the rectangle and the triangle separately and then add them together which would result in 330in. I personally do not think you should use the trapezoid formula even though they said it is a trapezoid (a trapezoid is usually not shaped like that) but if you want to it would result in 270in. 

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Flip a coin three times. You will win $2 for each heads. What is the expected winning (expectation of your winning)
Romashka [77]

The three coins could land any these 8 ways:

HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

P(3 heads) = 1 way out of 8  or 1/8

P(2 heads) = 3 ways out of 8 or 3/8

P(1 head) = 3 ways out of 8 or 3/8

P(0 heads) = 1 way out of 8 or 1/8

x=Winnings  P(x)  E(x)=x�P(x)

    $3      1/8      $.375

    $2      3/8      $.75

    $1      3/8      $.375

  -$10      1/8     -$1.25

---------------------------

Total expectation =   $ .25

7 0
3 years ago
S - 1/3 equals 4/9 so S equals what?
bekas [8.4K]
s -  \frac{1}{3} =  \frac{4}{9} \\ \\ s =  \frac{4}{9} +  \frac{1}{3} \\ \\ s =  \frac{7}{9} \\ \\ Answer: \fbox {s = 7/9} \ or \ \fbox {s = 0.7778}
5 0
3 years ago
Katie gives Maggie half of her pencils. Maggie keeps 5 pencils and gives the rest to Jamil. A. Write an expression for the numbe
Alexandra [31]

Here's what I mean when I write <em>x/</em><em>2</em><em> </em><em>JUST </em><em>IN </em><em>CASE.</em>

а.

Let the total number of pencils be x, then this implies that Maggie received <em>x/</em>2 pencils from Katie. Maggie keeps 5 and give the rest to Jamil, this means

that Jamil receives

<em>x/</em>2-5 pencils.

b. Expression of pencils given to Jamil is: <em>x/</em>2-5

Substitute <em>x</em><em>=</em><em>1</em><em>6</em><em> </em>in this expression: <em>x/</em>2-5

Simplify and evaluate: = 8-5= 3

Maggie gives 3 pencils to Jamil.

c. Expression of pencils given to Jamil is: x/2-5 to

Equate this expression with 1 to form an equation and solve for <em>x</em> all, the total

number of pencils if Jamil received 1 pencil:

<em>x/</em>2 - 5 = 1

Solve for x:

<em>x</em> = 2(1+ 5)

Evaluate:

<em>x</em> = 2(6) = 12

Katie had 12 pencils if Jamil received 1 pencil.

RESULT

a. Expression of number of pencils given to Jamil is <em>x</em>/2-5, where x is total number of pencils.

b. Maggie gives 3 pencils to Jamil.

c. Katie had 12 pencils if Jamil received 1 pencil.

5 0
3 years ago
Records indicate that for parts coming out a hydraulic repair shop at an airplane rework facility, 30\% will have a shaft defect
mrs_skeptik [129]

Answer:

P(A|B) = P(A∩B)/P(B) = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

Step-by-step explanation:

Conditional probability P(A|B) can be expressed as;

P(A|B) = P(A∩B)/P(B) .....1

Given;

30% will have a shaft defect,

15% will have a bushing defect,

and 65% will be defect-free

Total probability = 100% = P(shaft or/and bushing defect) + P(defect free)

P(shaft or/and bushing defect) = 100% - P(defect free)

= 100% - 65% = 35%

And

P(shaft or/and bushing defect) = P(shaft def only) + P(bushing def only) + P(shaft and bushing defect)

P(shaft or/and bushing defect) = P(shaft defect) + P(bushing defect) - P(shaft and bushing defect)

Substituting the values we have;

35% = 30% + 15% - P(shaft and bushing defect)

P(shaft and bushing defect) = 45% - 35% = 10%

Let A="The item has at least one type of defect"; and B="The item has only a shaft defect".

P(A) = P(shaft or/and bushing defect) = 35%

P(B) = P(shaft only defect) = 30% - 10% = 20%

P(A∩B) = 20%

Substituting into equation 1

P(A|B) = P(A∩B)/P(B) = 20%/20%

P(A|B) = 1/1 = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

5 0
3 years ago
To be called the Order of the Maandor of minors nonzero in a Matrix
MissTica

Answer:

To be called the order of the matador of Minors nonzero in a matrix

C D Range of a matrix

4 0
3 years ago
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