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1 year ago

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A Web music store offers two versions of a popular song. The size of the standard version is 2.9 megabytes (MB). The size of the

high-quality version is 4.1 MB. Yesterday, there were 1360 downloads of the song, for a total download size of 4532 MB. How many downloads of the high-quality version were there?

1 answer:

aliina [53]1 year ago

7 0

The number of standard version download and high-quality download is 870 and 490 respectively.

<h3>Number of downloads of the high-quality version</h3>

let

Number of high-quality download = y
Number of standard version = x

x + y = 1360

2.9x + 4.1y = 4532

From (1)

x = 1360 - y

Substitute x = 1360 - y into (2)

2.9x + 4.1y = 4532

2.9(1360 - y) + 4.1y = 4532

3944 - 2.9y + 4.1y = 4532

- 2.9y + 4.1y = 4532 - 3944

1.2y = 588

y = 588/1.2

y = 490

Substitute y = 490 into (1)

x + y = 1360

x + 490 = 1360

x = 1360 - 490

x = 870

So therefore, number of standard version download and high-quality download is 870 and 490 respectively.

Learn more about simultaneous equation:

brainly.com/question/16863577

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3 years ago

A game consists of tossing a coin 3 times and noting its outcome each time. Hanif wins if he gets three heads or three tails, an

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Answer:

There is 75% probability that Hanif will lose the game.

Step-by-step explanation:

Number of outcomes on tossing a coin = 2

Whenever an experiment is repeated "r" times, the total number of outcomes is calculated as:

$n^{r}$

Here n is the number of outcomes of one event. Since for tossing of a coin, the number of outcomes for each event is 2, so n = 2

The experiment is performed 3 times, so r = 3

Therefore, the total number of outcomes for tossing a coin 3 times is:

$2^3 = 8$ outcomes

Hanif wins if either of these two condition is met:

1) He gets all heads. There is only 1 outcome in 8 outcomes in which we can get all heads

2) He gets all tails. There is only 1 outcome in 8 outcomes in which we can get all tails.

Therefore, there are 2 possible outcomes for which Hanif will be the winner. On all other outcomes he will loose. Since total number of outcomes is 8, the number of outcomes for which Hanif will loose = 8 - 2 = 6 outcomes

We have to find the probability that Hanif will loose the game. Since, probability is defined as the ratio of desired outcomes to total number of outcomes, the probability that Hanif will loose the game will be:

$\frac{6}{8} =\frac{3}{4} =0.75=75\%$

Therefore, there is 75% probability that Hanif will lose the game.

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3 years ago

A right △ABC is inscribed in circle k(O, r). Find the radius of this circle if:

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We have been given that a right △ABC is inscribed in circle k(O, r).

m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.

First of all, we will draw a diagram that represent the given scenario.

We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.

We will use sine to find side AB.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(30^{\circ})=\frac{AC}{AB}$

$\text{sin}(30^{\circ})=\frac{18}{AB}$

$AB=\frac{18}{\text{sin}(30^{\circ})}$

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4 years ago

Can someone help me with these 5 question I have attached?

Contact [7]

Example 2: x=10

Example 3: x=-1

Example 4: x=35

Example 5: a-b+c=9

Example 6: x=1, x=1/2

Further explanation:

<u>Example 2:</u>

$\sqrt{4x-4} =6$

Taking Square on both sides

$(\sqrt{4x-4})^2 =(6)^2\\4x-4=36\\4x=36+4\\4x=40\\\frac{4x}{4}=\frac{40}{4}\\x=10$

<u>Example 3:</u>

$9+\sqrt{4x+8}=11$

Subtracting 9 from both sides

$9-9+\sqrt{4x+8}=11-9\\\sqrt{4x+8}=2\\$

Taking Square on both sides

$(\sqrt{4x+8})^2=(2)^2\\4x+8=4\\4x=4-8\\4x=-4\\\frac{4x}{4}=-\frac{4}{4}\\x=-1$

<u>Example 4:</u>

$8+\sqrt{x+1}=2$

subtracting 8 from both sides

$8-8+\sqrt{x+1}=2-8\\\sqrt{x+1}=-6$

Taking Square on both sides

$(\sqrt{x+1})^2=(-6)^2\\x+1=36\\$

Subtracting 1 from both sides

$x+1-1=36-1\\x=35$

<u>Example 5:</u>

$\sqrt{a-b+c}=3$

Taking Square on both sides

$(\sqrt{a-b+c})^2=(3)^2\\a-b+c=9\\$

<u>Example 6:</u>

$2\sqrt{2x-1}=4x-2$

Taking square on both sides

$(2\sqrt{2x-1})^2=(4x-2)^2\\4(2x-1)=16x^2+4-16x\\8x-4=16x^2-16x+4\\8x=16x^2-16x+4+4\\8x=16x^2-16x+8\\16x^2-16x-8x+8=0\\16x^2-24x+8=0$

dividng whole equation by 8

$2x^2-3x+1=0\\2x^2-2x-x+1=\\2x(x-1)-1(x-1)=0\\(2x-1)(x-1)=0\\2x-1=0 => x=\frac{1}{2}\\x-1=0 => x=1$

Keywords: Radical Expressions, Examples

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