Solve 2(4a-3)=-2maths

chubhunter [2.5K]

The ratios as fractions are 6/8 and 9/11.
Since they are not compare because they have different denominators you must find the Least Common Multiple of the two fractions.
Since 8 and 11 both can go into 88, we can use that as our denominator.
6/8 times 11/11 equals 66/88 and 9/11 times 8/8 equals 72/88.
66/88 is less than 72/88.

Therefor, Mix B is the reddest mixture.

Hope this helped!! :)

8 0

3 years ago

5,5,3 Is this a triangle? Explain.

Vlad1618 [11]

Problem 1

Answer: Yes a triangle can be formed with side lengths 5,5,3

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Explanation:

Take any two sides and add them up. If we get a sum larger than the third side, then a triangle is possible. This is the triangle inequality theorem.

5+5 = 10 is larger than 3

5+3 = 8 is larger than 5

This shows a triangle is possible. The triangle is isosceles because two sides are the same length.

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Problem 2

Answer: Yes a triangle can be formed with side lengths 8,8,8

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Explanation:

This triangle is equilateral because all sides are the same length.

Take any two sides, add them up, and you'll find the sum is larger than the third side.

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Problem 3

Answer: No a triangle cannot be formed with sides 7,8,15

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Explanation:

Yes it is true that

8+15 = 23 is larger than 7

7+15 = 22 is larger than 8

but

7+8 = 15 is not larger than 15

So this means a triangle is not possible.

Imagine you had 3 strips of paper that were 7 inches, 8 inches and 15 inches long. The 7 and 8 inch strips add to 15 inches, but those two smaller strips only form a straight line. We cannot pull them so a triangle forms. If we did, then the third side would be smaller than 15 inches. This is one way to get hands on to see why the triangle inequality theorem works.

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Problem 4

Answer: Yes a triangle is possible with side lengths 5,6,10

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Explanation:

Same idea as before. We can take any two sides, add them, and get a sum larger than the third side. A triangle is possible.

5+6 = 11 is larger than 10
6+10 = 16 is larger than 5
5+10 = 15 is larger than 6

4 0

3 years ago

Which of the binomials below is a factor of this trinomial? x^2 + 3x - 4A. x+4B. x+8C. x-4D. x^2+4

Usimov [2.4K]

Given:

The equation is:

$x^2+3x-4$

Find-:

Binomials factor of the equation

Explanation-:

The quadratic equation,

$x^2+3x-4$

Solve for factor

$\begin{gathered} =x^2+3x-4 \\ \\ =x^2+4x-x-4 \\ \end{gathered}$

Then the factor is:

$\begin{gathered} =x^2+4x-x-4 \\ \\ =x(x+4)-1(x+4) \\ \\ =(x+4)(x-1) \end{gathered}$

So, the factor is x + 4

6 0

1 year ago

Dionne builds a pattern that is represented by the equation b = 2f + 6, where f is the figure number of the pattern and b is the

GenaCL600 [577]

I don't know i just want some points

Step-by-step explanation:

well thank you anyways hope someone else can help you i am sorry.

7 0

3 years ago

Please answer ASAP. The question is down below.

zheka24 [161]

Answer: 1) c 2) a 3) d

Step-by-step explanation:

$\cos \theta = \dfrac{adjacent}{hypotenuse}\quad \\\\\\\cos 42.1=\dfrac{4.7}{x}\\\\\\x=\dfrac{4.7}{\cos 42.1}\\\\\\\large\boxed{x=6.33}\\$

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Reference angle is the angle measurement from the x-axis. There is no such thing as a negative reference angle.

-183° is 3° from the x-axis so the reference angle is $\large\boxed{3^o}$

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Coterminal means the same angle location after one or more rotations either clockwise or counter-clockwise.

To find these angles, add or subtract 360° from the given angle to find one rotation, add or subtract 2(360°) from the given angle to find two rotations, etc.

To find ALL of the coterminals, add or subtract 360° as many times as the number of rotations. Rotations can only be integers. In other words, you can only have ± 1, 2, 3, ... rotations. You cannot have a fraction of a rotation.

Given: 203°

Coterminal angles: 203° ± k360°, k ∈ I

7 0

3 years ago

Solve 2(4a-3)=-2maths​

Solve 2(4a-3)=-2maths