Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
8
Step-by-step explanation:
The new height is 24
The original height is 3
24/3 is 8
The scale factor is 8
The answer is -7 hope this helps!
Team A scored a total of 80,597 points I believe
161,161 + 33 = 161,194
161,194 ÷2 = 80,597
80,597- 33 = 80,564
80,564 + 80,597 = 161,161
.5(20x-50y+36)-.25(-100x+40y-12)
10x-25y+18+25x-10y+3
35x-25y+18-10y+3
35x-35y+18+3
35x-35y+21