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3 years ago

Can someone help pls

Mathematics

2 answers:

Brums [2.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

10|5x-25|-50 = 500

|5x-25|=55

5x-25 = +-55

soo we have 2 possible answers:

5x = 80

x = 16

and

5x = -30

x = 6

The Answers in your thing are flawed. But if I were to guess, I would pick C

STALIN [3.7K]3 years ago

3 0

Answer:

-7x19 and that how u get ur answer

Step-by-step explanation:

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Katyanochek1 [597]

Answer:

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4 0

3 years ago

Read 2 more answers

Please help fast ^^

allsm [11]

The discriminante :
b^2-4ac

1^2 - 4 * -2 * -28 = 1 - 224 = -223

When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.

-223<0, so, 2x^2+x-28 = 0 has no real solutions.

Hope that helps :)

7 0

2 years ago

I have just one question, could someone please answer it?? (see linked file)

Annette [7]

The solution is x=1 and y=-2

Further explanation:

Given equations are:

$\frac{7}{2}x-\frac{1}{2}y=\frac{9}{2}\\3x-y=5$

Multiplying equation no. 1 with 2 will give us:

$7x-y=9$ Eqn 3

From equation no 2:

$3x-y=5\\-y=5-3x\\y=3x-5$

Putting the value of y in eqn 3

$7x-(3x-5)=9\\7x-3x+5=9\\4x=9-5\\4x=4\\\frac{4x}{4}=\frac{4}{4}\\x=1\\Putting\ x=1\ in\ equation\ 2\\3(1)-y=5\\3-y=5\\-y=5-3\\-y=2\\y=-2\\$

The solution is x=1 and y=-2

Keywords: Linear equations, Solution set

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

How many zeros in five million dollars

natka813 [3]

$5,000,000

6 zeros, 3 holding the hundreds, 3 holding the hundred thousands.

Hope this helps!

7 0

3 years ago

Solve for x. (e^x-e^-x)/((e^x+e^-x)=t

Sergio [31]

$\dfrac{e^x-e^{-x}}{e^x+e^{-x}}=t\\\\
\dfrac{e^{2x}-1}{e^{2x}+1}=t\\\\
e^{2x}-1=t(e^{2x}+1)\\\\
e^{2x}-1=e^{2x}t+t\\\\
e^{2x}-e^{2x}t=t+1\\\\
e^{2x}(1-t)=t+1\\\\
e^{2x}=\dfrac{t+1}{1-t}\\\\
e^{2x}=-\dfrac{t+1}{t-1}\\\\
2x=\ln\left(-\dfrac{t+1}{t-1}\right)\\\\
x=\dfrac{\ln\left(-\dfrac{t+1}{t-1}\right)}{2}\qquad t\in(-1,1)



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8 0

3 years ago

Read 2 more answers