Question

Triangle ABC , m∠A=45° and c = 16, find b.

Answer 1

Using the cosine function:

$\begin{gathered} \cos (\theta)=\frac{_{\text{ }}adjacent}{_{\text{ }}hypotenuse} \\ so\colon \\ \cos (45)=\frac{b}{16} \end{gathered}$

Solve for b:

$\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}$