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Pavlova-9 [17]
2 years ago
11

Triangle ABC , m∠A=45° and c = 16, find b.

Mathematics
1 answer:
zmey [24]2 years ago
5 0

Using the cosine function:

\begin{gathered} \cos (\theta)=\frac{_{\text{ }}adjacent}{_{\text{ }}hypotenuse} \\ so\colon \\ \cos (45)=\frac{b}{16} \end{gathered}

Solve for b:

\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}

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In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?
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Step-by-step explanation:

Given

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The question is illustrated with the attached image.

From the image, we have:

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