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1 year ago

Triangle ABC , m∠A=45° and c = 16, find b.

Mathematics

1 answer:

zmey [24]1 year ago

5 0

Using the cosine function:

$\begin{gathered} \cos (\theta)=\frac{_{\text{ }}adjacent}{_{\text{ }}hypotenuse} \\ so\colon \\ \cos (45)=\frac{b}{16} \end{gathered}$

Solve for b:

$\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}$

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SUBTRACT: (6x3 - 7x2) - (- 7x4 + 7x3 + 8x2)

RSB [31]

Answer:

-5

Step-by-step explanation:

“x” would be multiplication, right?

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2 years ago

one evening 1500 concert tickets were sold for the Jazz Fest. Tickets cost $30 for covered pavillion seats and $10 for lawn seat

snow_lady [41]

$x-number\ of\ tickets\ for\ pavilion\\1500-x-number\ of\ tickets\ for\ lawn\\\\30x+10(1500-x)=27000\\30x+15000-10x=27000\\30x-10x=27000-15000\\20x=12000\ \ \ \ \ \ \ \ |:20\\\\x=600\\1500-600=900$

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2 years ago

(-4)-(-2)-{(-5)-[(-7)+(-3)-(-8)]}

olasank [31]

Answer:

Explanation:

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3 years ago

What is a geometric sequence and arithmetic sequence?<br><br> ~MUST EXPLAIN~

Vadim26 [7]

A geometric sequence is one that involves addition or subtraction. One example would be "In an auditorium, the 1st row has 25 seats. The 2nd has 30. The 3rd has 35. How many does the 4th have? Take the formula, x + 5. All you do is simply add 5.

An arithmetic sequence is one that involves multiplication or division. For example, "Jon receives 5 dollars each week. If he waits for 5 months, how much money will he have? Honestly, all you have to do is think about the formula. x * 5. x would be the number of weeks.

I know my answer is not as good as the verified one, but it is simpler and easier to understand. I apologize if it isn't good enough.

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2 years ago

Please answer I’ll rate brainlyest

12345 [234]

Answer:

$5P3*6C4=60*15=900$

Step-by-step explanation:

$5P3$ refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

$5P3=\frac{5!}{(5-3)!}$

The factorial of an integer n is evaluated as;

$n!=n*(n-1)*(n-2)*(n-3).......3*2*1$

Using this concept, the above expression can now be simplified as follows;

$5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60$

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, $6C4$ refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

$6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15$

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

$5P3*6C4=60*15=900$

3 0

2 years ago