A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
The equations shows a difference of squares are:
<u>10y²- 4x²</u> $ <u>6y²- x²</u>
Step-by-step explanation:
the difference of two squares is a squared number subtracted from another squared number, it has the general from Ax² - By²
We will check the options to find which shows a difference of squares.
1) 10y²- 4x²
The expression is similar to the general form, so the equation represents a difference of squares.
It can be factored as (√10 y + 2x )( √10 y - 2x)
2) 6y²- x²
The expression is similar to the general form, so the equation represents a difference of squares.
It can be factored as (√6y + x )( √6y - x)
3) 8x²−40x+25
The expression is not similar to the general form, so the equation does not represent a difference of squares.
4) 64x²-48x+9
The expression is not similar to the general form, so the equation does not represent a difference of squares.
Answer:
<u><em>Measure of angle A is 27 7/9 degrees.</em></u>
Step-by-step explanation:
Lets call measure of angle A is <em><u>X-10</u></em>
Lets call measure of angle B is X
Lets call measure of angle D is 2.5X+20
We know that the sum of triangles add up to 180 degrees
X+X-10+2.5X+20=180
X=37 7/9
So measure of angle A is 27 7/9 degrees.
I hope this is right. :)
Answer:
Step-by-step explanation:
we know that
If the three points are collinear
then
we have
A (1, 2/3), B (x, -4/5), and C (-1/2, 4)
The formula to calculate the slope between two points is equal to
step 1
Find the slope AB
we have
substitute in the formula
step 2
Find the slope AC
we have
substitute in the formula
step 3
Equate the slopes
solve for x
simplify
