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Kazeer [188]
3 years ago
15

Write a polynomial function in standard form with zeros at −3, −1, and 1.

Mathematics
1 answer:
Annette [7]3 years ago
8 0

Answer:

f(x) = {x}^{3}  + 3 {x}^{2}  - x -3

Step-by-step explanation:

The given polynomial has zeros at:

x=−3, x=−1, and x=1.

This means that:

x+3, x+1, and x-1 are all factors of this polynomial.

The factored form of this polynomial is :

f(x) = (x + 3)(x + 1)(x - 1)

We expand the last two factors using difference of two squares.

f(x) = (x + 3)( {x}^{2}  - 1)

f(x) = x ( {x}^{2}  - 1) + 3( {x}^{2}  - 1)

f(x) = {x}^{3}  - x+ 3 {x}^{2}  -3

f(x) = {x}^{3}  + 3 {x}^{2}  - x -3

This is the standard form because it is now in decreasing powers of x.

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